How to print third column to last column?

Question

I\'m trying to remove the first two columns (of which I\'m not interested in) from a DbgView log file. I can\'t seem to find an example that prints from column 3 onwards unt

Answer 1

Jonathan Feinberg's answer prints each field on a separate line. You could use printf to rebuild the record for output on the same line, but you can also just move the fields a jump to the left.

awk '{for (i=1; i<=NF-2; i++) $i = $(i+2); NF-=2; print}' logfile

Answer 2

If you want to print the columns after the 3rd for example in the same line, you can use:

awk '{for(i=3; i<=NF; ++i) printf "%s ", $i; print ""}'

For example:

Mar 09:39 20180301_123131.jpg
Mar 13:28 20180301_124304.jpg
Mar 13:35 20180301_124358.jpg
Feb 09:45 Cisco_WebEx_Add-On.dmg
Feb 12:49 Docker.dmg
Feb 09:04 Grammarly.dmg
Feb 09:20 Payslip 10459 %2828-02-2018%29.pdf

It will print:

20180301_123131.jpg
20180301_124304.jpg
20180301_124358.jpg
Cisco_WebEx_Add-On.dmg
Docker.dmg
Grammarly.dmg
Payslip 10459 %2828-02-2018%29.pdf

As we can see, the payslip even with space, shows in the correct line.

Answer 3

Perl solution:

perl -lane 'splice @F,0,2; print join " ",@F' file

These command-line options are used:

• -n loop around every line of the input file, do not automatically print every line

• -l removes newlines before processing, and adds them back in afterwards

• -a autosplit mode – split input lines into the @F array. Defaults to splitting on whitespace

• -e execute the perl code

splice @F,0,2 cleanly removes columns 0 and 1 from the @F array

join " ",@F joins the elements of the @F array, using a space in-between each element

If your input file is comma-delimited, rather than space-delimited, use -F, -lane

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Python solution:

python -c "import sys;[sys.stdout.write(' '.join(line.split()[2:]) + '\n') for line in sys.stdin]" < file

Answer 4

...or a simpler solution: cut -f 3- INPUTFILE just add the correct delimiter (-d) and you got the same effect.

Answer 5

Well, you can easily accomplish the same effect using a regular expression. Assuming the separator is a space, it would look like:

awk '{ sub(/[^ ]+ +[^ ]+ +/, ""); print }'

Answer 6

awk '{$1=$2=$3=""}1' file

NB: this method will leave "blanks" in 1,2,3 fields but not a problem if you just want to look at output.