How to remove an element from an array in Swift

Question

How can I unset/remove an element from an array in Apple\'s new language Swift?

Here\'s some code:

let animals = [\"cats\", \"dogs\", \"chimps\", \"m         


        

Answer 1

This should do it (not tested):

animals[2...3] = []

Edit: and you need to make it a var, not a let, otherwise it's an immutable constant.

Answer 2

I use this extension, almost same as Varun's, but this one (below) is all-purpose:

 extension Array where Element: Equatable  {
        mutating func delete(element: Iterator.Element) {
                self = self.filter{$0 != element }
        }
    }

Answer 3

If you have array of custom Objects, you can search by specific property like this:

if let index = doctorsInArea.firstIndex(where: {$0.id == doctor.id}){
    doctorsInArea.remove(at: index)
}

or if you want to search by name for example

if let index = doctorsInArea.firstIndex(where: {$0.name == doctor.name}){
    doctorsInArea.remove(at: index)
}

Answer 4

Given

var animals = ["cats", "dogs", "chimps", "moose"]

Remove first element

animals.removeFirst() // "cats"
print(animals)        // ["dogs", "chimps", "moose"]

Remove last element

animals.removeLast() // "moose"
print(animals)       // ["cats", "dogs", "chimps"]

Remove element at index

animals.remove(at: 2) // "chimps"
print(animals)           // ["cats", "dogs", "moose"]

Remove element of unknown index

For only one element

if let index = animals.firstIndex(of: "chimps") {
    animals.remove(at: index)
}
print(animals) // ["cats", "dogs", "moose"]

For multiple elements

var animals = ["cats", "dogs", "chimps", "moose", "chimps"]

animals = animals.filter(){$0 != "chimps"}
print(animals) // ["cats", "dogs", "moose"]

Notes

• The above methods modify the array in place (except for filter) and return the element that was removed.
• Swift Guide to Map Filter Reduce
• If you don't want to modify the original array, you can use dropFirst or dropLast to create a new array.

Updated to Swift 5.2

Answer 5

If you don't know the index of the element that you want to remove, and the element is conform the Equatable protocol, you can do:

animals.remove(at: animals.firstIndex(of: "dogs")!)

See Equatable protocol answer:How do I do indexOfObject or a proper containsObject

Answer 6

To remove elements from an array, use the remove(at:), removeLast() and removeAll().

yourArray = [1,2,3,4]

Remove the value at 2 position

yourArray.remove(at: 2)

Remove the last value from array

yourArray.removeLast()

Removes all members from the set

yourArray.removeAll()