How do I find out the files in the current directory which do not contain the word foo
(using grep
)?
You will actually need:
find . -not -ipath '.*svn*' -exec grep -H -E -o -c "foo" {} \; | grep :0\$
You can do it with grep alone (without find).
grep -riL "foo" .
This is the explanation of the parameters used on grep
-L, --files-without-match
each file processed.
-R, -r, --recursive
Recursively search subdirectories listed.
-i, --ignore-case
Perform case insensitive matching.
If you use l
(lowercased) you will get the opposite (files with matches)
-l, --files-with-matches
Only the names of files containing selected lines are written
If you are using git, this searches all of the tracked files:
git grep -L "foo"
and you can search in a subset of tracked files if you have ** subdirectory globbing turned on (shopt -s globstar
in .bashrc, see this):
git grep -L "foo" -- **/*.cpp
another alternative when grep doesn't have the -L option (IBM AIX for example), with nothing but grep and the shell :
for file in * ; do grep -q 'my_pattern' $file || echo $file ; done