Is there a better way of writing v = (v == 0 ? 1 : 0); [closed]

Answer 1

If you don't care about any possibility other than 1:

v = v ? 0 : 1;

In the above case, v will end up being 1 if v is 0, false, undefined or null. Take care using this kind of approach - v will be 0 even if v is "hello world".

Answer 2

Just for kicks: v = Math.pow(v-1,v) also toggles between 1 and 0.

Answer 3

You can simply use:

v = 1 - v;

This of course assumes that the variable is initialised properly, i.e. that it only has the value 0 or 1.

Another method that is shorter but uses a less common operator:

v ^= 1;

Edit:

To be clear; I never approached this question as code golf, just to find a short way of doing the task without using any obscuring tricks like side effects of operators.

Answer 4

Another way to do it:

v = ~(v|-v) >>> 31;

Answer 5

If you're guaranteed your input is either a 1 or a 0, then you could use:

v = 2+~v;

Answer 6

If possible values for v are only 0 and 1, then for any integer x, the expression: v = Math.pow((Math.pow(x, v) - x), v); will toggle the value.

I know this is an ugly solution and the OP was not looking for this...but I was thinking about just another solution when I was in the loo :P