Prevent JavaScript Number function from rounding big numbers

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自闭症患者 2020-11-28 16:17

I have a string value \' 9223372036854775807 \'. I use Number() function in JavaScript to convert it to a number value using the following Code

var numericVa         


        
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  • 2020-11-28 16:22

    JavaScript numbers are Double Precision Floats; the largest integer that can be precisely stored is 2^53 (9007199254740992). If you actually need it in a number you have some fun math ahead of you, or you can use a library such as big.js

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  • 2020-11-28 16:23

    You can compare strings that represent big integers as strings-

    a longer string of integers is larger, otherwise compare characters in order.

    You can sort an array of integer-strings

    function compareBigInts(a, b){
        if(a.length== b.length) return a>b? 1:-1;
        return a.length-b.length;
    }
    

    or return the larger of two strings of digits

    function getBiggestBigInts(a, b){
        if(a.length== b.length) return a>b? a:b;
        return a.length>b.length? a: b;
    }
    

    //examples

    var n1= '9223372036854775807', n2= '9223372056854775807',
    n3= '9223',n2= '9223372056854775817',n4= '9223372056854775';
    

    getBiggestBigInts(n1,n2);>> 9223372056854775807

    [n1,n2,n3,n4].sort(compareBigInts);>>

    9223
    9223372056854775
    9223372036854775807
    9223372056854775817
    

    Just make sure you are comparing strings.

    (If you use '-' minus values,a 'bigger' string value is less)

    By the way,you sort big decimals by splitting on the decimal point and comparing the integer parts. If the integers are the same length and are equal, look at the the decimal parts.

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  • 2020-11-28 16:26

    It's seems that your number is greater than 2^53, biggest integer number in javascript which can be represented without loosing precision (see this question).

    If you really need to operate big numbers, you could use special libraries like this one: https://github.com/peterolson/BigInteger.js

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  • 2020-11-28 16:30

    The problem why Number('9223372036854775807') produce 9223372036854776000 is that JavaScript have limited precision (up to 16 digits) and you need 19 digits.

    One of solutions might be using of java script big-numbers library:

    // Initializa library:
    var bn = new BigNumbers();
    
    // Create numbers to compare:
    var baseNumber = bn.of('9223372036854775807');
    var toCompareNumber = bn.of('9223372036854775808');
    
    // Compare:
    if(baseNumber.lessOrEquals(toCompareNumber)) {
        console.log('This should be logged');
    } else {
        console.log('This should NOT be logged');
    }
    
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