SQLite parameter substitution and quotes

Question

I have this line that works OK:

c.execute(\'select cleanseq from cleanseqs WHERE newID=\"%s\"\'%name)

But I want to use SQLite parameter su

Answer 1

The library will handle quoting and escaping for you. Simply write your query like this:

c.execute('SELECT cleanseq FROM cleanseqs WHERE newID=?', (name,))

Answer 2

about """If I delete the quotes sourronding the ?, it works. But I want the quotes to remain there since I remember that there are cases where I need them."""

What you remember from when you were building the whole SQL statement yourself is irrelevant.

The new story is: mark with a ? each place in the SQL statement where you want a value substituted then pass in a tuple containing one value per ? -- it's that simple; the wrapper will quote any strings to make sure that they are acceptable SQL constants.

Answer 3

Regular User

just noticed that you'll have to do this manual by using the unsecure method of sql_string = "other sql surger here.. fieldname=\""+value+"\";"

its the only way you'll get it to parse correctly. using SQLite for win ce. and well left me with no other alternative, just escape your values before putting them in else you'll most likely end up with a very sad database from sql injections :'( lol

Answer 4

I find the named-parameter binding style much more readable -- and sqlite3 supports it:

c.execute('SELECT cleanseq FROM cleanseqs WHERE newID=:t', locals())

Note: passing {'t': t} or dict(t=t) instead of locals() would be more punctiliously correct, but in my opinion it would interfere with readability when there are several parameters and/or longer names. In any case, I do find the :t better than the ?;-).

Answer 5

Lose the quotes around ?

c.execute('select cleanseq from cleanseqs WHERE newID=?',(t,))

It's treating it as the string "?".

Do you need to use double quotes around the whole expression, instead of singles?

Answer 6

To anyone who like me found this thread and got really frustrated by people ignoring the fact that sometimes you can't just ignore the quotes (because you're using say a LIKE command) you can fix this by doing something to the effect of:

var = name + "%"
c.execute('SELECT foo FROM bar WHERE name LIKE ?',(var,))

This will allow you to substitute in wildcards in this situation.