Using if(isset($_POST['submit'])) to not display echo when script is open is not working

Question

I have a little problem with my if(isset($_POST[\'submit\'])) code. What I want is some echos and a table to not appear when the script is open but I do want it

Answer 1

You need to give your submit <input> a name or it won't be available using $_POST['submit']:

<p><input type="submit" value="Submit" name="submit" /></p>

Answer 2

The $_post function need the name value like:

<input type="submit" value"Submit" name="example">

Call

$var = strip_tags($_POST['example']);
if (isset($var)){
    // your code here
}

Answer 3

You must give a name to your submit button

<input type="submit" value"Submit" name="login">

Then you can call the button with $_POST['login']

Answer 4

Another option is to use

$_SERVER['REQUEST_METHOD'] == 'POST'

Answer 5

You never named your submit button, so as far as the form is concerned it's just an action.

Either:

1. Name the submit button (<input type="submit" name="submit" ... />)
2. Test if (!empty($_POST)) instead to detect when data has been posted.

Remember that keys in the $_POST superglobal only appear for named input elements. So, unless the element has the name attribute, it won't come through to $_POST (or $_GET/$_REQUEST)

Answer 6

What you're checking

if(isset($_POST['submit']))

but there's no variable name called "submit". well i want you to understand why it doesn't works. lets imagine if you give your submit button name delete <input type="submit" value="Submit" name="delete" /> and check if(isset($_POST['delete'])) then it works in this code you didn't give any name to submit button and checking its exist or not with isset(); function so php didn't find any variable like "submit" so its not working now try this :

<input type="submit" name="submit" value="Submit" />