How to refresh or show immediately in datagridview after inserting?

Question

After entering data into all the textbox, and after clicking the submit button, it won\'t immediately show in the datagridview, I need to reopen the form in order to see the

Answer 1

Use LoadPatientRecords() after a successful insertion.

Try the below code

private void btnSubmit_Click(object sender, EventArgs e)
{
        if (btnSubmit.Text == "Clear")
        {
            btnSubmit.Text = "Submit";

            txtpFirstName.Focus();
        }
        else
        {
           btnSubmit.Text = "Clear";
           int result = AddPatientRecord();
           if (result > 0)
           {
               MessageBox.Show("Insert Successful");

               LoadPatientRecords();
           }
           else
               MessageBox.Show("Insert Fail");
         }
}

Answer 2

Try refreshing the datagrid after each insert

datagridview1.update();
datagridview1.refresh();  

Hope this helps you!

Answer 3

You can set the datagridview DataSource to null and rebind it again.

private void button1_Click(object sender, EventArgs e)
{
    myAccesscon.ConnectionString = connectionString;

    dataGridView.DataSource = null;
    dataGridView.Update();
    dataGridView.Refresh();
    OleDbCommand cmd = new OleDbCommand(sql, myAccesscon);
    myAccesscon.Open();
    cmd.CommandType = CommandType.Text;
    OleDbDataAdapter da = new OleDbDataAdapter(cmd);
    DataTable bookings = new DataTable();
    da.Fill(bookings);
    dataGridView.DataSource = bookings;
    myAccesscon.Close();
}

Answer 4

Only need to fill datagrid again like this:

this.XXXTableAdapter.Fill(this.DataSet.XXX);

If you use automaticlly connect from dataGridView this code create automaticlly in Form_Load()

Answer 5

In the form designer add a new timer using the toolbox. In properties set "Enabled" equal to "True".

The set the DataGridView to equal your new data in the timer

Answer 6

I don't know if you resolved your problem, but a simple way to resolve this is rebuilding the DataSource (it is a property) of your datagridview. For example:

grdPatient.DataSource = MethodThatReturnList();

So, in that MethodThatReturnList() you can build a List (List is a class) with all the items you need. In my case, I have a method that return the values for two columns that I have on my datagridview.

Pasch.