How to sort DOM elements while selecting in jQuery?

Question

I have the following DIVs on my page:

  Div 3


  Div 2



        
                      

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Answer 1

I would use the Array.sort method. http://jsfiddle.net/LJWrg/

var divArr = $("div[id*=pi_div]");
function cleanId(id) {
    return parseInt(id.replace("pi_div",""),10);
}
Array.prototype.sort.call(divArr,function(a,b) {
    return cleanId(a.id) > cleanId(b.id);
});
divArr.each(function(){
    console.log(this.id);
});

jQuery does come with this method internally defined, so you can shorten it to this (however it uses undocumented methods) http://jsfiddle.net/LJWrg/1/:

var divArr = $("div[id*=pi_div]");
function cleanId(id) {
    return parseInt(id.replace("pi_div",""),10);
}
divArr.sort(function(a,b) {
    return cleanId(a.id) > cleanId(b.id);
});
divArr.each(function(){
    console.log(this.id);
});

Answer 2

$("div[id^=pi_div]").sort(function (a, b) {
    return a.id.replace('pi_div', '') > b.id.replace('pi_div', '');
}).foo();

http://jsfiddle.net/KrX7t/

Answer 3

If you also want to sort them visibly on the page

$('div[id^="pi_div"]').sort(function (a, b) {
    var re = /[^\d]/g;
    return ~~a.id.replace(re, '') > ~~b.id.replace(re, '');
})
.appendTo("#container");

Note the ~~ which converts the values into integers, otherwise they would be compared as strings.

See http://jsfiddle.net/Xjc2T/

Answer 4

You can call .sort() before calling .each()

$("div[id*=pi_div]").sort(function(a,b){
    if(a.id < b.id) {
        return -1;
    } else {
        return 1;
    }
}).each(function() { console.log($(this).attr("id"));});

EDIT: I was wondering why the other answers are removing the pi_div part of the id and I get it. If you compare based on the "strings" pi_div10 will come before pi_div2.