I\'m working with Spring and Hibernate to develop web applications in Java. Let\'s assume that I have a table. When I delete some records from this table, sometimes I need t
With reference to Oracle's ALTER SEQUENCE documentation,
You require to pass current maximum value of the primary key column to generate the next sequence number.
If you keep on deleting some latest records, and want to reuse the already generated sequence values, you may require to restart this sequence again and again. Dropping a sequence may lead to SQLException if the server receives a request for next value before the sequence is ready to serve.
You can also find some helpful notes on Oracle Sequences here.
This trick works for me. In my sequence (USERSUTPL_USERUTPL_SQ) the last number was 53. The last id in my table was 83
SELECT MAX(ID) FROM USERSUTPL_USERUTPL
Then 83 - 53 = 31. So:
ALTER SEQUENCE USERSUTPL_USERUTPL_SQ INCREMENT BY +31;
SELECT USERSUTPL_USERUTPL_SQ.NEXTVAL FROM dual;
ALTER SEQUENCE USERSUTPL_USERUTPL_SQ INCREMENT BY 1;
And its changes the last number. :D
The following also works (increases your sequence value by 100):
select my_sequence.nextval from dual connect by level <= 100;
What happens if you have 20 records and delete records 5-10? You have a gap in the middle that re-setting the sequence will not solve. Sequences will never generate a gap free sequence of numbers, a perfect 1, 2 .. n.
If you call .nextval
and don't use the value it's gone. Are you going to drop and re-create the sequence? If you start an insert and cancel it and Oracle rolls back what you've done those values are gone. If you set nocache
then you will have less gaps but at a cost of a hit to performance; is it worth it?
Your cache should be set to the number of inserts you expect to do at any one time across all sessions to avoid any performance issues. Sequences are designed to provide a very quick, scalable way of creating a surrogate key without any locks etc not to re-generate the set of positive integers.
At the end of the day it shouldn't matter in the slightest. If you're relying on an unbroken sequence as the key of your table then you have a problem with your data rather than sequences.
To actually answer your question you would need to:
Finding the maximum value means you'd need to re-create the sequence dynamically at the cost of another hit to performance.
If you try to insert something into your table whilst this is happening it will fail, and may invalidate any triggers or other objects which use the sequence:
declare
l_max_value number;
begin
select max(id)
into l_max_value
from my_table;
execute immediate 'drop sequence my_sequence_name';
-- nocache is not recommended if you are inserting more than
-- one row at a time, or inserting with any speed at all.
execute immediate 'create sequence my_sequence_name
start with ' || l_max_value
|| ' increment by 1
nomaxvalue
nocycle
nocache';
end;
/
As I say this is not recommended and you should just ignore any gaps.
Contrary to the documentation's recommendation there is, as Jeffrey Kemp suggested in the comments, a way to do this without dropping and re-creating the sequence.
Namely, by:
id
in your table and the current value of the sequence. The benefits of this are that the object still exists so and triggers, grants etc are still maintained. The downside, as I see it, is that if another session increments by this negative number at the same time as yours you can go back too far.
Here's a demonstration:
SQL> create sequence test_seq
2 start with 1
3 increment by 1
4 nomaxvalue
5 nocycle
6 nocache;
Sequence created.
SQL>
SQL> create table tmp_test ( id number(16) );
Table created.
SQL>
SQL> declare
2 l_nextval number;
3 begin
4
5 for i in 1 .. 20 loop
6 insert into tmp_test values ( test_seq.nextval );
7 end loop;
8
9 end;
10 /
PL/SQL procedure successfully completed.
SQL>
SQL> select test_seq.currval from dual;
CURRVAL
----------
20
SQL>
SQL> delete from tmp_test where id > 15;
5 rows deleted.
SQL> commit;
Commit complete.
SQL>
SQL> declare
2
3 l_max_id number;
4 l_max_seq number;
5
6 begin
7
8 -- Get the maximum ID
9 select max(id) into l_max_id
10 from tmp_test;
11
12 -- Get the current sequence value;
13 select test_seq.currval into l_max_seq
14 from dual;
15
16 -- Alter the sequence to increment by the difference ( -5 in this case )
.
17 execute immediate 'alter sequence test_seq
18 increment by ' || ( l_max_id - l_max_seq );
19
20 -- 'increment' by -5
21 select test_seq.nextval into l_max_seq
22 from dual;
23
24 -- Change the sequence back to normal
25 execute immediate 'alter sequence test_seq
26 increment by 1';
27
28 end;
29 /
PL/SQL procedure successfully completed.
SQL>
SQL> select test_seq.currval from dual;
CURRVAL
----------
15
SQL>