How to escape the backslashes and the automatically generated escape character in file path in java

Question

I have very small and simple problem but I am not getting solutions on it. Actually I am getting a CSV file path using file chooser. I am entering the data in this csv file

Answer 1

You have to use escaping in the initial literal (filepath), for example:

String filepath="C:\\title.csv"

Answer 2

you need to use:

 String filepath2=filepath.replace("\\","\\\\");

Answer 3

String filepath2=filepath.replace("\","\\") is not valid code - \ is a special character in string literals and needs to be escaped:

String escapedFilepath = filepath.replace("\\","\\\\"); //double all backslashes

Answer 4

Use a double slash in Java string literal to escape a slash :

String s = "c:\\new folder\\title.csv";

If an end user enters a string in a JFileChooser, the string variable will contain all the characters entered by the user. Escaping is only needed when using String literals in Java source code.

And use a prepared statement to insert strings into a database table. This will properly escape special characters and avoid SQL injection attacks. Read more about prepared statements in the Java tutorial about JDBC.