Submit a form using jQuery [closed]

Answer 1

I recommend a generic solution so you don't have to add the code for every form. Use the jquery form plugin (http://jquery.malsup.com/form/) and add this code.

$(function(){
$('form.ajax_submit').submit(function() {
    $(this).ajaxSubmit();
            //validation and other stuff
        return false; 
});

});

Answer 2

From the manual: jQuery Doc

$("form:first").submit();

Answer 3

jQuery("a[id=atag]").click( function(){

    jQuery('#form-id').submit();      

            **OR**

    jQuery(this).parents("#form-id").submit();
});

Answer 4

If the button is located between the form tags, I prefer this version:

$('.my-button').click(function (event) {
    var $target = $( event.target );
    $target.closest("form").submit();
});

Answer 5

My approach slightly Different Change the button into submit button and then click

$("#submit").click(function(event) {
$(this).attr('type','submit');
$(this).click();
});

Answer 6

this will send a form with preloader :

var a=$('#yourform').serialize();
$.ajax({
    type:'post',
    url:'receiver url',
    data:a,
    beforeSend:function(){
        launchpreloader();
    },
    complete:function(){
        stopPreloader();
    },
    success:function(result){
         alert(result);
    }
});

i'have some trick to make a form data post reformed with random method http://www.jackart4.com/article.html