I am really confused about the query that needing to return top N rows having biggest values on particular column.
For example, if the rows N-1, N, N + 1
You should use self join for this.
For E.g. on below sample table
CREATE TABLE `employee` (
`ID` INT(11) AUTO_INCREMENT PRIMARY KEY,
`NAME` VARCHAR(50) NOT NULL,
`SALARY` INT(11) NOT NULL ,
JOINING_DATE TIMESTAMP
) ENGINE=MYISAM
INSERT INTO employee (NAME,salary,joining_date) VALUES('JAMES',50000,'2010-02-02'),
('GARGI',60000,'2010-02-02'),('DAN',30000,'2010-02-02'),('JOHN',10000,'2010-02-02'),('MICHEL',70000,'2010-02-02'),
('STIEVE',50000,'2010-02-02'),('CALRK',20000,'2010-02-02'),('BINNY',50000,'2010-02-02'),('SMITH',40000,'2010-02-02'),
('ROBIN',60000,'2010-02-02'),('CRIS',80000,'2010-02-02');
With the above table-data set up Query to find employees having top 3 salaries would be :
SELECT e1.* FROM
(SELECT DISTINCT salary FROM Employee ORDER BY salary DESC LIMIT 3 ) S1
JOIN employee e1
ON e1.salary = s1.salary
ORDER BY e1.salary DESC
TIP:-
If you need top 4 then just change LIMIT 3
to LIMIT 4
If you do:
select *
from t
order by value desc
limit N
You will get the top N rows.
If you do:
select *
from t join
(select min(value) as cutoff
from (select value
from t
order by value
limit N
) tlim
) tlim
on t.value >= tlim;
Or you could phrase this a bit more simply as:
select *
from t join
(select value
from t
order by value
limit N
) tlim
on t.value = tlim.value;
The following is conceptually what you want to do, but it might not work in MySQL:
select *
from t
where t.value >= ANY (select value from t order by value limit N)
Use the following SQL query.
SELECT salary FROM salesperson
ORDER BY salary DESC
LIMIT 2,1