I am trying to get the highest number from a simple array:
data = [4, 2, 6, 1, 3, 7, 5, 3];
alert(Math.max(data));
I have read that if eve
If you have to use the Math.max function and one number of the array might be undefined, you could use:
x = Math.max(undefined || 0, 5)
console.log(x) // prints 5
The reason why your code doesn't work is because Math.max
is expecting each parameter to be a valid number. This is indicated in the documentation as follows:
If at least one of arguments cannot be converted to a number, the result is NaN.
In your instance you are only providing 1 argument, and that 1 value is an array not a number (it doesn't go as far as checking what is in an array, it just stops at knowing it isn't a valid number).
One possible solution is to explicitly call the function by passing an array of arguments. Like so:
Math.max.apply(Math, data);
What this effectively does is the same as if you manually specified each argument without an array:
Math.max(4, 2, 6, 1, 3, 7, 5, 3);
And as you can see, each argument is now a valid number, so it will work as expected.
if you see doc for Math.max you can see next description
Because max() is a static method of Math, you always use it as Math.max(), rather than as a method of a Math object you created (Math is not a constructor).
If no arguments are given, the result is -Infinity.
If at least one of arguments cannot be converted to a number, the result is NaN.
When you call Math.max
with array parameter like
Math.max([1,2,3])
you call this function with one parameter - [1,2,3]
and javascript try convert it to number and get ("1,2,3" -> NaN) fail.
So result as expected - NaN
NOTE: if array with just one number - all work correctly
Math.max([23]) // return 23
because [23] -> "23" -> 23
and covert to Number is done.
If you want get max element from array you should use apply function, like
Math.max.apply(Math,[1,2,3])
or you can use the new spread operator
Math.max(...[1,2,3])
It's not working because you are passing an array as the parameter instead of comma separated numbers. Try spreading the array like this:
data = [4, 2, 6, 1, 3, 7, 5, 3];
alert(Math.max(...data));