Accept comma and dot as decimal separator [duplicate]

Answer 1

var nfInfo = new System.Globalization.CultureInfo(lang, false)
{
    NumberFormat =
    {
        NumberDecimalSeparator = "."
    }
};
Thread.CurrentThread.CurrentCulture = nfInfo;
Thread.CurrentThread.CurrentUICulture = nfInfo;

Answer 2

Thanks to accepted answer I ended up with the following implementation to handle float, double and decimal.

public abstract class FloatingPointModelBinderBase<T> : DefaultModelBinder
{
    protected abstract Func<string, IFormatProvider, T> ConvertFunc { get; }

    public override object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext)
    {
        var valueProviderResult = bindingContext.ValueProvider.GetValue(bindingContext.ModelName);
        if (valueProviderResult == null) return base.BindModel(controllerContext, bindingContext);
        try
        {
            return ConvertFunc.Invoke(valueProviderResult.AttemptedValue, CultureInfo.CurrentUICulture);
        }
        catch (FormatException)
        {
            // If format error then fallback to InvariantCulture instead of current UI culture
            return ConvertFunc.Invoke(valueProviderResult.AttemptedValue, CultureInfo.InvariantCulture);
        }
    }
}

public class DecimalModelBinder : FloatingPointModelBinderBase<decimal>
{
    protected override Func<string, IFormatProvider, decimal> ConvertFunc => Convert.ToDecimal;
}

public class DoubleModelBinder : FloatingPointModelBinderBase<double>
{
    protected override Func<string, IFormatProvider, double> ConvertFunc => Convert.ToDouble;
}

public class SingleModelBinder : FloatingPointModelBinderBase<float>
{
    protected override Func<string, IFormatProvider, float> ConvertFunc => Convert.ToSingle;
}

Then you just have to set your ModelBinders on Application_Start method

ModelBinders.Binders[typeof(float)] = new SingleModelBinder();
ModelBinders.Binders[typeof(double)] = new DoubleModelBinder();
ModelBinders.Binders[typeof(decimal)] = new DecimalModelBinder();

Answer 3

Cleanest way is to implement your own model binder

public class DecimalModelBinder : DefaultModelBinder
{
    public override object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext)
    {
        var valueProviderResult = bindingContext.ValueProvider.GetValue(bindingContext.ModelName);

        return valueProviderResult == null ? base.BindModel(controllerContext, bindingContext) : Convert.ToDecimal(valueProviderResult.AttemptedValue);
        // of course replace with your custom conversion logic
    }    
}

And register it inside Application_Start():

ModelBinders.Binders.Add(typeof(decimal), new DecimalModelBinder());
ModelBinders.Binders.Add(typeof(decimal?), new DecimalModelBinder());

Credits : Default ASP.NET MVC 3 model binder doesn't bind decimal properties

Answer 4

To properly handle group separator, just replace

Convert.ToDecimal(valueProviderResult.AttemptedValue);

in selected answer with

Decimal.Parse(valueProviderResult.AttemptedValue, NumberStyles.Currency);