Is there any easy/short way to get the worksheet object of the new sheet you get when you copy a worksheet?
ActiveWorkbook.Sheets(\
It is correct that hidden worksheets cause the new worksheet index to be non-sequential on either side of the source worksheet. I found that Rachel's answer works if you're copying before. But you'd have to adjust it if you're copying after.
Once the model is visible and copied, the new worksheet object is simply the ActiveSheet whether you copy the source before or after.
As a preference, you could replace:
Set newSheet = .Previous
with Set newSheet = Application.ActiveSheet
.
Hope this is helpful to some of you.
UPDATE:
Dim ThisSheet As Worksheet
Dim NewSheet As Worksheet
Set ThisSheet = ActiveWorkbook.Sheets("Sheet1")
ThisSheet.Copy
Set NewSheet = Application.ActiveSheet
Dim sht
With ActiveWorkbook
.Sheets("Sheet1").Copy After:= .Sheets("Sheet2")
Set sht = .Sheets(.Sheets("Sheet2").Index + 1)
End With
Old post but wasn't sure about unhiding sheets or adding suffixes to names.
This is my approach:
Sub DuplicateSheet()
Dim position As Integer
Dim wbNewSheet As Worksheet
position = GetFirstVisiblePostion
ThisWorkbook.Worksheets("Original").Copy Before:=ThisWorkbook.Sheets(position)
Set wbNewSheet = ThisWorkbook.Sheets(position)
Debug.Print "Duplicated name:" & wbNewSheet.Name, "Duplicated position:" & wbNewSheet.Index
End Sub
Function GetFirstVisiblePostion() As Integer
Dim wbSheet As Worksheet
Dim position As Integer
For Each wbSheet In ThisWorkbook.Sheets
If wbSheet.Visible = xlSheetVisible Then
position = wbSheet.Index
Exit For
End If
Next
GetFirstVisiblePostion = position
End Function
I believe I have finally nailed this issue - it's been driving me nuts, also! It really would have been nice if MS made Copy return a sheet object, same as the Add method...
The thing is, the index which VBA allocates a newly copied sheet is actually not determined... as others have noted, it very much depends on hidden sheets. In fact, I think the expression Sheets(n) is actually interpreted as "the nth visible sheet". So unless you write a loop testing every sheet's visible property, using this in code is fraught with danger, unless the workbook is protected so users cannot mess with sheets visible property. Too hard...
My solution to this dilemma is:
Here's my code - which now seems to be bullet-proof...
Dim sh as worksheet
Dim last_is_visible as boolean
With ActiveWorkbook
last_is_visible = .Sheets(.Sheets.Count).Visible
.Sheets(Sheets.Count).Visible = True
.Sheets("Template").Copy After:=.Sheets(Sheets.Count)
Set sh=.Sheets(Sheets.Count)
if not last_is_visible then .Sheets(Sheets.Count-1).Visible = False
sh.Move After:=.Sheets("OtherSheet")
End With
In my case, I had something like this (H indicating a hidden sheet)
1... 2... 3(H)... 4(H)... 5(H)... 6... 7... 8(H)... 9(H)
.Copy After:=.Sheets(2) actually creates a new sheet BEFORE the next VISIBLE sheet - ie, it became the new index 6. NOT at index 3, as you might expect.
Hope that helps ;-)
I realise this post is over a year old, but I came here looking for an answer to the same issue regarding copying sheets and unexpected results caused by hidden sheets. None of the above really suited what I wanted mainly because of the structure of my workbook. Essentailly it has a very large number of sheets and what is displayed is driven by a user selecting the specific functionality, plus the order of the visible sheets was importnat to me so i didnt want to mess with those. So my end solution was to rely on Excels default naming convention for copied sheets, and explictly rename the new sheet by name. Code sample below (as an aside, my workbook has 42 sheets and only 7 are permanently visible, and the
after:=Sheets(Sheets.count)
put my copied sheet in the middle of the 42 sheets, depending on what sheets are visible at the time.
Select Case DCSType
Case "Radiology"
'Copy the appropriate Template to a new sheet at the end
TemplateRAD.Copy after:=Sheets(Sheets.count)
wsToCopyName = TemplateRAD.Name & " (2)"
'rename it as "Template"
Sheets(wsToCopyName).Name = "Template"
'Copy the appropriate val_Request to a new sheet at the end
valRequestRad.Copy after:=Sheets(Sheets.count)
'rename it as "val_Request"
wsToCopyName = valRequestRad.Name & " (2)"
Sheets(wsToCopyName).Name = "val_Request"
Case "Pathology"
'Copy the appropriate Template to a new sheet at the end
TemplatePath.Copy after:=Sheets(Sheets.count)
wsToCopyName = TemplatePath.Name & " (2)"
'rename it as "Template"
Sheets(wsToCopyName).Name = "Template"
'Copy the appropriate val_Request to a new sheet at the end
valRequestPath.Copy after:=Sheets(Sheets.count)
wsToCopyName = valRequestPath.Name & " (2)"
'rename it as "val_Request"
Sheets(wsToCopyName).Name = "val_Request"
End Select
Anyway, posted just in case its useful to anyone else