Finding contents of one file in another file

Question

I\'m using the following shell script to find the contents of one file into another:

#!/bin/ksh
file=\"/home/nimish/contents.txt\"

while read -r line; do
           


        

Answer 1

Another solution:

• use awk and create your own hash(e.g. ahash), all controlled by yourself.
• replace $0 to $i and you can match any fields you want.

---

awk -F"," '
{  
   if (nowfile==""){ nowfile = FILENAME;  }

   if(FILENAME == nowfile)
   {
     hash[$0]=$0;
   }
   else
   {
       if($0 ~ hash[$0])
       {  
           print $0
       }
   }
} '  xx yy

Answer 2

I don't think you really need a script to perform what you're trying to do.

One command is enough. In my case, I needed an identification number in column 11 in a CSV file (with ";" as separator):

grep -f <(awk -F";" '{print $11}' FILE_TO_EXTRACT_PATTERNS_FROM.csv) TARGET_FILE.csv

Answer 3

grep itself is able to do so. Simply use the flag -f:

grep -f <patterns> <file>

<patterns> is a file containing one pattern in each line; and <file> is the file in which you want to search things.

Note that, to force grep to consider each line a pattern, even if the contents of each line look like a regular expression, you should use the flag -F, --fixed-strings.

grep -F -f <patterns> <file>

If your file is a CSV, as you said, you may do:

grep -f <(tr ',' '\n' < data.csv) <file>

---

As an example, consider the file "a.txt", with the following lines:

alpha
0891234
beta

Now, the file "b.txt", with the lines:

Alpha
0808080
0891234
bEtA

The output of the following command is:

grep -f "a.txt" "b.txt"
0891234

You don't need at all to for-loop here; grep itself offers this feature.

---

Now using your file names:

#!/bin/bash
patterns="/home/nimish/contents.txt"
search="/home/nimish/another_file.csv"
grep -f <(tr ',' '\n' < "${patterns}") "${search}"

You may change ',' to the separator you have in your file.