Read a file line by line assigning the value to a variable

Question

I have the following .txt file:

Marco
Paolo
Antonio

I want to read it line-by-line, and for each

Answer 1

For proper error handling:

#!/bin/bash

set -Ee    
trap "echo error" EXIT    
test -e ${FILENAME} || exit
while read -r line
do
    echo ${line}
done < ${FILENAME}

Answer 2

Use:

filename=$1
IFS=$'\n'
for next in `cat $filename`; do
    echo "$next read from $filename" 
done
exit 0

If you have set IFS differently you will get odd results.

Answer 3

#! /bin/bash
cat filename | while read LINE; do
    echo $LINE
done

Answer 4

The following will just print out the content of the file:

cat $Path/FileName.txt

while read line;
do
echo $line     
done

Answer 5

I encourage you to use the -r flag for read which stands for:

-r  Do not treat a backslash character in any special way. Consider each
    backslash to be part of the input line.

I am citing from man 1 read.

Another thing is to take a filename as an argument.

Here is updated code:

#!/usr/bin/bash
filename="$1"
while read -r line; do
    name="$line"
    echo "Name read from file - $name"
done < "$filename"

Answer 6

If you need to process both the input file and user input (or anything else from stdin), then use the following solution:

#!/bin/bash
exec 3<"$1"
while IFS='' read -r -u 3 line || [[ -n "$line" ]]; do
    read -p "> $line (Press Enter to continue)"
done

Based on the accepted answer and on the bash-hackers redirection tutorial.

Here, we open the file descriptor 3 for the file passed as the script argument and tell read to use this descriptor as input (-u 3). Thus, we leave the default input descriptor (0) attached to a terminal or another input source, able to read user input.