Run multiple UI Threads

Question

Skip to the bottom for the question; this is just some extra info

I am using a component (GeckoFX) to render some websites, well fine, yet it can only be us

Answer 1

Seems like it is possible.

I took backgrounder, opened TestApp, and created a new Form1 on thread/message pump #2:

private void button2_Click(object sender, EventArgs e) {
    helper.Background(() => {
        Form1 form2 = new Form1();
        form2.Show();
    });
}

The second window responds to mouse clicks etc.

Haven't actually verified if everything looks right, the freebie Visual Studio Express Edition I'm using is missing the "Threads" debug window, ahem. So I'm a bit in the dark. It seems to work, though. Let me know :-).

Answer 2

GeckoFx doesn't require a form.

GeckoWebBrowser wb = new GeckoWebBrowser();
wb.CreateControl(); //<-- the magic lays here!
wb.DocumentCompleted += delegate{ MessageBox.Show(wb.DocumentTitle); };
wb.Navigate("http://mysite.com");

Answer 3

I don't think that what you ask is really what you want but creating a message pump per thread is easy, you just have to call Application.Run once per thread.

static class Program
{
    /// <summary>
    /// The main entry point for the application.
    /// </summary>
    [STAThread]
    static void Main()
    {
        Thread t1 = new Thread(Main_);
        Thread t2 = new Thread(Main_);

        t1.Start();
        t2.Start();

        t1.Join();
        t2.Join();
    }

    static void Main_()
    {
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        Application.Run(new Form1());
    }
}

Answer 4

Use Application.DoEvent().
or
Create multiply threading forms:

    Thread form2Thread;
    Form2 form2;

    private void Form1_Load(object sender, EventArgs e)
    {
        form2Thread = new Thread(RunForm2);
        form2Thread.SetApartmentState(ApartmentState.STA);
        form2Thread.Name = "Form2 Thread";   // looks nice in Output window
        form2Thread.Start();
    }

    public void RunForm2()
    {
        form2 = new Form2();
        Application.Run(form2);
    }