How to get the current working directory in Java?

Question

I want to access my current working directory using java.

My code :

 String current = new java.io.File( \".\" ).getCanonicalPath();
        System.ou         


        

Answer 1

None of the answers posted here worked for me. Here is what did work:

java.nio.file.Paths.get(
  getClass().getProtectionDomain().getCodeSource().getLocation().toURI()
);

Edit: The final version in my code:

URL myURL = getClass().getProtectionDomain().getCodeSource().getLocation();
java.net.URI myURI = null;
try {
    myURI = myURL.toURI();
} catch (URISyntaxException e1) 
{}
return java.nio.file.Paths.get(myURI).toFile().toString()

Answer 2

this is current directory name

String path="/home/prasad/Desktop/folderName";
File folder = new File(path);
String folderName=folder.getAbsoluteFile().getName();

this is current directory path

String path=folder.getPath();

Answer 3

See: http://docs.oracle.com/javase/tutorial/essential/io/pathOps.html

Using java.nio.file.Path and java.nio.file.Paths, you can do the following to show what Java thinks is your current path. This for 7 and on, and uses NIO.

Path currentRelativePath = Paths.get("");
String s = currentRelativePath.toAbsolutePath().toString();
System.out.println("Current relative path is: " + s);

This outputs Current relative path is: /Users/george/NetBeansProjects/Tutorials that in my case is where I ran the class from. Constructing paths in a relative way, by not using a leading separator to indicate you are constructing an absolute path, will use this relative path as the starting point.

Answer 4

This is the solution for me

File currentDir = new File("");

Answer 5

this.getClass().getClassLoader().getResource("").getPath()

Answer 6

The following works on Java 7 and up (see here for documentation).

import java.nio.file.Paths;

Paths.get(".").toAbsolutePath().normalize().toString();