I need to send this XML
NO
1900&
Another option would be file_get_contents()
:
// $xml_str = your xml
// $url = target url
$post_data = array('xml' => $xml_str);
$stream_options = array(
'http' => array(
'method' => 'POST',
'header' => 'Content-type: application/x-www-form-urlencoded' . "\r\n",
'content' => http_build_query($post_data)));
$context = stream_context_create($stream_options);
$response = file_get_contents($url, null, $context);
you can use cURL library for posting data: http://www.php.net/curl
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch, CURLOPT_URL, "http://websiteURL");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "XML=".$xmlcontent."&password=".$password."&etc=etc");
$content=curl_exec($ch);
where postfield contains XML you need to send - you will need to name the postfield the API service (Clickatell I guess) expects