Simplest way to plot 3d surface given 3d points

Question

I have a lot (289) of 3d points with xyz coordinates which looks like:

With plotting simp

Answer 1

Solution with matplotlib:

#!/usr/bin/python3

import sys

import matplotlib
import matplotlib.pyplot as plt
from matplotlib.ticker import MaxNLocator
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D

import numpy
from numpy.random import randn
from scipy import array, newaxis


# ======
## data:

DATA = array([
    [-0.807237702464, 0.904373229492, 111.428744443],
    [-0.802470821517, 0.832159465335, 98.572957317],
    [-0.801052795982, 0.744231916692, 86.485869328],
    [-0.802505546206, 0.642324228721, 75.279804677],
    [-0.804158144115, 0.52882485495, 65.112895758],
    [-0.806418040943, 0.405733109371, 56.1627277595],
    [-0.808515314192, 0.275100227689, 48.508994388],
    [-0.809879521648, 0.139140394575, 42.1027499025],
    [-0.810645106092, -7.48279012695e-06, 36.8668106345],
    [-0.810676720161, -0.139773175337, 32.714580273],
    [-0.811308686707, -0.277276065449, 29.5977405865],
    [-0.812331692291, -0.40975978382, 27.6210856615],
    [-0.816075037319, -0.535615685086, 27.2420699235],
    [-0.823691366944, -0.654350489595, 29.1823292975],
    [-0.836688691603, -0.765630198427, 34.2275056775],
    [-0.854984518665, -0.86845932028, 43.029581434],
    [-0.879261949054, -0.961799684483, 55.9594146815],
    [-0.740499820944, 0.901631050387, 97.0261463995],
    [-0.735011699497, 0.82881933383, 84.971061395],
    [-0.733021568161, 0.740454485354, 73.733621269],
    [-0.732821755233, 0.638770044767, 63.3815970475],
    [-0.733876941678, 0.525818698874, 54.0655910105],
    [-0.735055978521, 0.403303715698, 45.90859502],
    [-0.736448900325, 0.273425879041, 38.935709456],
    [-0.737556181137, 0.13826504904, 33.096106049],
    [-0.738278724065, -9.73058423274e-06, 28.359664343],
    [-0.738507612286, -0.138781586244, 24.627237837],
    [-0.738539663773, -0.275090412979, 21.857410904],
    [-0.739099040189, -0.406068448513, 20.1110519655],
    [-0.741152200369, -0.529726022182, 19.7019157715],
])

Xs = DATA[:,0]
Ys = DATA[:,1]
Zs = DATA[:,2]


# ======
## plot:

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

surf = ax.plot_trisurf(Xs, Ys, Zs, cmap=cm.jet, linewidth=0)
fig.colorbar(surf)

ax.xaxis.set_major_locator(MaxNLocator(5))
ax.yaxis.set_major_locator(MaxNLocator(6))
ax.zaxis.set_major_locator(MaxNLocator(5))

fig.tight_layout()

plt.show() # or:
# fig.savefig('3D.png')

Result:

Probably not very beautiful. But it will be, if You provide more points.

Answer 2

Please have a look at Axes3D.plot_surface or at the other Axes3D methods. You can find examples and inspirations here, here, or here.

Edit:

Z-Data that is not on a regular X-Y-grid (equal distances between grid points in one dimension) is not trivial to plot as a triangulated surface. For a given set of irregular (X, Y) coordinates, there are multiple possible triangulations. One triangulation can be calculated via a "nearest neighbor" Delaunay algorithm. This can be done in matplotlib. However, it still is a bit tedious:

http://matplotlib.1069221.n5.nabble.com/Plotting-3D-Irregularly-Triangulated-Surfaces-An-Example-td9652.html

It looks like support will be improved:

http://matplotlib.org/examples/pylab_examples/tripcolor_demo.html http://matplotlib.1069221.n5.nabble.com/Custom-plot-trisurf-triangulations-tt39003.html

With the help of http://docs.enthought.com/mayavi/mayavi/auto/example_surface_from_irregular_data.html I was able to come up with a very simple solution based on mayavi:

import numpy as np
from mayavi import mlab

X = np.array([0, 1, 0, 1, 0.75])
Y = np.array([0, 0, 1, 1, 0.75])
Z = np.array([1, 1, 1, 1, 2])

# Define the points in 3D space
# including color code based on Z coordinate.
pts = mlab.points3d(X, Y, Z, Z)

# Triangulate based on X, Y with Delaunay 2D algorithm.
# Save resulting triangulation.
mesh = mlab.pipeline.delaunay2d(pts)

# Remove the point representation from the plot
pts.remove()

# Draw a surface based on the triangulation
surf = mlab.pipeline.surface(mesh)

# Simple plot.
mlab.xlabel("x")
mlab.ylabel("y")
mlab.zlabel("z")
mlab.show()

This is a very simple example based on 5 points. 4 of them are on z-level 1:

(0, 0) (0, 1) (1, 0) (1, 1)

One of them is on z-level 2:

(0.75, 0.75)

The Delaunay algorithm gets the triangulation right and the surface is drawn as expected:

I ran the above code on Windows after installing Python(x,y) with the command

ipython -wthread script.py