How to read only 5 last line of the text file in PHP?

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陌清茗
陌清茗 2020-11-28 08:45

I have a file named file.txt which is update by adding lines to it.

I am reading it by this code:

$fp = fopen(\"file.txt\", \"r\");
$da         


        
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18条回答
  • 2020-11-28 09:15

    Least amount of ram, and outputs well. I agree with Paul Dixon...

    $lines=array();
    $fp = fopen("userlog.txt", "r");
    while(!feof($fp))
    {
     $line = fgets($fp, 4096);
     array_push($lines, $line);
     if (count($lines)>25)
       array_shift($lines);
    }
    fclose($fp);
    
    while ($a <= 10) {
    $a++;
    echo "<br>".$lines[$a];
    }
    
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  • 2020-11-28 09:17

    If your lines are separated by a CR or LF you would try exploding your $data variable:

    $lines = explode("\n", $data);
    

    $lines should end up being an array and you can work out the number of records using sizeof() and just get the last 5.

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  • 2020-11-28 09:19

    This is a common interview question. Here's what I wrote last year when I was asked this question. Remember that code you get on Stack Overflow is licensed with the Creative Commons Share-Alike with attribution required.

    <?php
    
    /**
     * Demonstrate an efficient way to search the last 100 lines of a file
     * containing roughly ten million lines for a sample string. This should
     * function without having to process each line of the file (and without making
     * use of the “tail” command or any external system commands). 
     * Attribution: https://stackoverflow.com/a/2961731/3389585
     */
    
    $filename = '/opt/local/apache2/logs/karwin-access_log';
    $searchString = 'index.php';
    $numLines = 100;
    $maxLineLength = 200;
    
    $fp = fopen($filename, 'r');
    
    $data = fseek($fp, -($numLines * $maxLineLength), SEEK_END);
    
    $lines = array();
    while (!feof($fp)) {
      $lines[] = fgets($fp);
    }
    
    $c = count($lines);
    $i = $c >= $numLines? $c-$numLines: 0;
    for (; $i<$c; ++$i) {
      if ($pos = strpos($lines[$i], $searchString)) {
        echo $lines[$i];
      }
    }
    

    This solution does make an assumption about the maximum line length. The interviewer asked me how I would solve the problem if I couldn't make that assumption, and had to accommodate lines that were potentially longer than any max length I chose.

    I told him that any software project has to make certain assumptions, but I could test if $c was less than the desired number of lines, and if it isn't, fseek() back further incrementally (doubling each time) until we do get enough lines.

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  • 2020-11-28 09:23
    $dosya = "../dosya.txt";
    $array = explode("\n", file_get_contents($dosya));
    $reversed = array_reverse($array);
    for($x = 0; $x < 6; $x++) 
    {
        echo $reversed[$x];
    }
    
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  • 2020-11-28 09:24

    If you're on a linux system you could do this:

    $lines = `tail -5 /path/to/file.txt`;
    

    Otherwise you'll have to count lines and take the last 5, something like:

    $all_lines = file('file.txt');
    $last_5 = array_slice($all_lines , -5);
    
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  • 2020-11-28 09:24

    You can use my small helper library (2 functions)

    https://github.com/jasir/file-helpers

    Then just use:

    //read last 5 lines
    $lines = \jasir\FileHelpers\FileHelpers::readLastLines($pathToFile, 5);
    
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