How to remove all characters before a specific character in Python?

Question

I\'d like to remove all characters before a designated character or set of characters (for example):

intro = \"<>I\'m Tom.\"

Now I\'d

Answer 1

import re

date_div = "Blah blah\nblah, Updated: Aug. 23, 2012 Blah blah Updated: Feb. 13, 2019"

up_to_word = ":"
rx_to_first = r'^.*?{}'.format(re.escape(up_to_word))
rx_to_last = r'^.*{}'.format(re.escape(up_to_word))

# (Dot.) In the default mode, this matches any character except a newline. 
# If the DOTALL flag has been specified, this matches any character including a newline.

print("Remove all up to the first occurrence of the word including it:")
print(re.sub(rx_to_first, '', date_div, flags=re.DOTALL).strip())

print("Remove all up to the last occurrence of the word including it:")
print(re.sub(rx_to_last, '', date_div, flags=re.DOTALL).strip())

Answer 2

If you know the character position of where to start deleting, you can use slice notation:

intro = intro[2:]

Instead of knowing where to start, if you know the characters to remove then you could use the lstrip() function:

intro = intro.lstrip("<>")

Answer 3

intro="These are unwanted characters <> I'm Tom"
indx = intro.find("I")#position of 'I'
intro = intro[indx:]
print(intro)

Answer 4

import re
intro = "<>I'm Tom."
re.sub(r'<>I', 'I', intro)

Answer 5

str = "<>I'm Tom."
temp = str.split("I",1)
temp[0]=temp[0].replace("<>","")
str = "I".join(temp)

Answer 6

Use re.sub. Just match all the chars upto I then replace the matched chars with I.

re.sub(r'^.*?I', 'I', stri)