Show a child form in the centre of Parent form in C#

Question

I create a new form and call from the parent form as follows:

loginForm = new SubLogin();   
loginForm.Show();

I need to display the chi

Answer 1

Make a Windows Form , then put option for it : CenterParent then use this Code :

yourChildFormName x = new yourChildFormName();
x.ShowDialog();

Answer 2

    protected override void OnLoad(EventArgs e) {
        base.OnLoad(e);

        CenterToParent();
    }

Answer 3

As a sub form i think it's not gonna Start in the middle of the parent form until you Show it as a Dialog. .......... Form2.ShowDialog();

i was about to make About Form. and this is perfect that's i am searching for. and untill you close the About_form you cant Touch/click anythings of parents Form once you Click for About_Form (in my case) .Coz its Showing as Dialog

Answer 4

Why not use this?

LoginForm.WindowStartupLocation = Windows.WindowStartupLocation.CenterOwner 

(vb.net)

Answer 5

It works in all cases, swap Form1 for your main form.

Popup popup = new Popup();
popup.StartPosition = System.Windows.Forms.FormStartPosition.Manual;
popup.Location = new System.Drawing.Point((Form1.ActiveForm.Location.X + Form1.ActiveForm.Width / 2) - (popup.Width / 2),(Form1.ActiveForm.Location.Y + Form1.ActiveForm.Height / 2) - (popup.Height / 2));
popup.Show(Form1.ActiveForm);

Answer 6

When you want to use a non-blocking window (show() instead of showDialog()), this not work:

//not work with .Show(this) but only with .ShowDialog(this)
loginForm.StartPosition = FormStartPosition.CenterParent;
loginForm.Show(this);

In this case, you can use this code to center child form before display the form:

//this = the parent
frmDownloadPercent frm = new frmDownloadPercent();
frm.Show(this); //this = the parent form
//here the tips
frm.Top = this.Top + ((this.Height / 2) - (frm.Height / 2));
frm.Left = this.Left + ((this.Width / 2) - (frm.Width / 2));