Calculating the angle between the line defined by two points

Question

I\'m currently developing a simple 2D game for Android. I have a stationary object that\'s situated in the center of the screen and I\'m trying to get that object to rotate

Answer 1

Had a need for similar functionality myself, so after much hair pulling I came up with the function below

/**
 * Fetches angle relative to screen centre point
 * where 3 O'Clock is 0 and 12 O'Clock is 270 degrees
 * 
 * @param screenPoint
 * @return angle in degress from 0-360.
 */
public double getAngle(Point screenPoint) {
    double dx = screenPoint.getX() - mCentreX;
    // Minus to correct for coord re-mapping
    double dy = -(screenPoint.getY() - mCentreY);

    double inRads = Math.atan2(dy, dx);

    // We need to map to coord system when 0 degree is at 3 O'clock, 270 at 12 O'clock
    if (inRads < 0)
        inRads = Math.abs(inRads);
    else
        inRads = 2 * Math.PI - inRads;

    return Math.toDegrees(inRads);
}

Answer 2

with pygame:

dy = p1.y - p2.y
dX = p2.x - p1.x

rads = atan2(dy,dx)
degs = degrees(rads)
if degs < 0 :
   degs +=90

it work for me

Answer 3

in android i did this using kotlin:

private fun angleBetweenPoints(a: PointF, b: PointF): Double {
        val deltaY = abs(b.y - a.y)
        val deltaX = abs(b.x - a.x)
        return Math.toDegrees(atan2(deltaY.toDouble(), deltaX.toDouble()))
    }

Answer 4

Assumptions: x is the horizontal axis, and increases when moving from left to right. y is the vertical axis, and increases from bottom to top. (touch_x, touch_y) is the point selected by the user. (center_x, center_y) is the point at the center of the screen. theta is measured counter-clockwise from the +x axis. Then:

delta_x = touch_x - center_x
delta_y = touch_y - center_y
theta_radians = atan2(delta_y, delta_x)

Edit: you mentioned in a comment that y increases from top to bottom. In that case,

delta_y = center_y - touch_y

But it would be more correct to describe this as expressing (touch_x, touch_y) in polar coordinates relative to (center_x, center_y). As ChrisF mentioned, the idea of taking an "angle between two points" is not well defined.

Answer 5

A few answers here have tried to explain the "screen" issue where top left is 0,0 and bottom right is (positive) screen width, screen height. Most grids have the Y axis as positive above X not below.

The following method will work with screen values instead of "grid" values. The only difference to the excepted answer is the Y values are inverted.

/**
 * Work out the angle from the x horizontal winding anti-clockwise 
 * in screen space. 
 * 
 * The value returned from the following should be 315. 
 * <pre>
 * x,y -------------
 *     |  1,1
 *     |    \
 *     |     \
 *     |     2,2
 * </pre>
 * @param p1
 * @param p2
 * @return - a double from 0 to 360
 */
public static double angleOf(PointF p1, PointF p2) {
    // NOTE: Remember that most math has the Y axis as positive above the X.
    // However, for screens we have Y as positive below. For this reason, 
    // the Y values are inverted to get the expected results.
    final double deltaY = (p1.y - p2.y);
    final double deltaX = (p2.x - p1.x);
    final double result = Math.toDegrees(Math.atan2(deltaY, deltaX)); 
    return (result < 0) ? (360d + result) : result;
}

Answer 6

"the origin is at the top-left of the screen and the Y-Coordinate increases going down, while the X-Coordinate increases to the right like normal. I guess my question becomes, do I have to convert the screen coordinates to Cartesian coordinates before applying the above formula?"

If you were calculating the angle using Cartesian coordinates, and both points were in quadrant 1 (where x>0 and y>0), the situation would be identical to screen pixel coordinates (except for the upside-down-Y thing. If you negate Y to get it right-side up, it becomes quadrant 4...). Converting screen pixel coordinates to Cartesian doesnt really change the angle.