Get the nth item of a generator in Python

Question

Is there a more syntactically concise way of writing the following?

gen = (i for i in xrange(10))
index = 5
for i, v in enumerate(gen):
    if i is index:
           


        

Answer 1

You could do this, using count as an example generator:

from itertools import islice, count
next(islice(count(), n, n+1))