Does anyone know how to add 2 binary numbers, entered as binary, in Java?
For example, 1010 + 10 = 1100
.
package Assignment19thDec;
import java.util.Scanner;
public class addTwoBinaryNumbers {
private static Scanner sc;
public static void main(String[] args) {
sc = new Scanner(System.in);
System.out.println("Enter 1st Binary Number");
int number1=sc.nextInt();
int reminder1=0;
int number2=sc.nextInt();
int reminder2=0;
int carry=0;
double sumResult=0 ;int add = 0
;
int n;
int power=0;
while (number1>0 || number2>0) {
/*System.out.println(number1 + " " +number2);*/
reminder1=number1%10;
number1=number1/10;
reminder2=number2%10;
number2=number2/10;
/*System.out.println(reminder1 +" "+ reminder2);*/
if(reminder1>1 || reminder2>1 ) {
System.out.println("not a binary number");
System.exit(0);
}
n=reminder1+reminder2+carry;
switch(n) {
case 0:
add=0; carry=0;
break;
case 1: add=1; carry=0;
break;
case 2: add=0; carry=1;
break;
case 3: add=1;carry=1;
break;
default: System.out.println("not a binary number ");
}
sumResult=add*(Math.pow(10, power))+sumResult;
power++;
}
sumResult=carry*(Math.pow(10, power))+sumResult;
System.out.println("\n"+(int)sumResult);
}
}
Use Integer.parseInt(String, int radix).
public static String addBinary(){
// The two input Strings, containing the binary representation of the two values:
String input0 = "1010";
String input1 = "10";
// Use as radix 2 because it's binary
int number0 = Integer.parseInt(input0, 2);
int number1 = Integer.parseInt(input1, 2);
int sum = number0 + number1;
return Integer.toBinaryString(sum); //returns the answer as a binary value;
}
import java.util.Scanner;
{
public static void main(String[] args)
{
String b1,b2;
Scanner sc= new Scanner(System.in);
System.out.println("Enter 1st binary no. : ") ;
b1=sc.next();
System.out.println("Enter 2nd binary no. : ") ;
b2=sc.next();
int num1=Integer.parseInt(b1,2);
int num2=Integer.parseInt(b2,2);
int sum=num1+num2;
System.out.println("Additon is : "+Integer.toBinaryString(sum));
}
}