Python function to convert seconds into minutes, hours, and days

Question

Question: Write a program that asks the user to enter a number of seconds, and works as follows:

• There are 60 seconds in a minute. If the number of seconds

Answer 1

Do it the other way around subtracting the secs as needed, and don't call it time; there's a package with that name:

def sec_to_time():
    sec = int( input ('Enter the number of seconds:'.strip()) )

    days = sec / 86400
    sec -= 86400*days

    hrs = sec / 3600
    sec -= 3600*hrs

    mins = sec / 60
    sec -= 60*mins
    print days, ':', hrs, ':', mins, ':', sec

Answer 2

#1 min = 60
#1 hour = 60 * 60 = 3600
#1 day = 60 * 60 * 24 = 86400

    x=input('enter a positive integer: ')

    t=int(x)

    day= t//86400
    hour= (t-(day*86400))//3600
    minit= (t - ((day*86400) + (hour*3600)))//60
    seconds= t - ((day*86400) + (hour*3600) + (minit*60))
    print( day, 'days' , hour,' hours', minit, 'minutes',seconds,' seconds')

Answer 3

To convert seconds (as string) into datetime, this could also help. You get number of days and seconds. Seconds can be further converted into minutes and hours.

from datetime import datetime, timedelta
sec = timedelta(seconds=(int(input('Enter the number of seconds: '))))
time = str(sec)

Answer 4

seconds_in_day = 86400
seconds_in_hour = 3600
seconds_in_minute = 60

seconds = int(input("Enter a number of seconds: "))

days = seconds // seconds_in_day
seconds = seconds - (days * seconds_in_day)

hours = seconds // seconds_in_hour
seconds = seconds - (hours * seconds_in_hour)

minutes = seconds // seconds_in_minute
seconds = seconds - (minutes * seconds_in_minute)

print("{0:.0f} days, {1:.0f} hours, {2:.0f} minutes, {3:.0f} seconds.".format(
    days, hours, minutes, seconds))

Answer 5

I'm not entirely sure if you want it, but I had a similar task and needed to remove a field if it is zero. For example, 86401 seconds would show "1 days, 1 seconds" instead of "1 days, 0 hours, 0 minutes, 1 seconds". THe following code does that.

def secondsToText(secs):
    days = secs//86400
    hours = (secs - days*86400)//3600
    minutes = (secs - days*86400 - hours*3600)//60
    seconds = secs - days*86400 - hours*3600 - minutes*60
    result = ("{} days, ".format(days) if days else "") + \
    ("{} hours, ".format(hours) if hours else "") + \
    ("{} minutes, ".format(minutes) if minutes else "") + \
    ("{} seconds, ".format(seconds) if seconds else "")
    return result

EDIT: a slightly better version that handles pluralization of words.

def secondsToText(secs):
    days = secs//86400
    hours = (secs - days*86400)//3600
    minutes = (secs - days*86400 - hours*3600)//60
    seconds = secs - days*86400 - hours*3600 - minutes*60
    result = ("{0} day{1}, ".format(days, "s" if days!=1 else "") if days else "") + \
    ("{0} hour{1}, ".format(hours, "s" if hours!=1 else "") if hours else "") + \
    ("{0} minute{1}, ".format(minutes, "s" if minutes!=1 else "") if minutes else "") + \
    ("{0} second{1}, ".format(seconds, "s" if seconds!=1 else "") if seconds else "")
    return result

EDIT2: created a gist that does that in several languages

Answer 6

This will convert n seconds into d days, h hours, m minutes, and s seconds.

from datetime import datetime, timedelta

def GetTime():
    sec = timedelta(seconds=int(input('Enter the number of seconds: ')))
    d = datetime(1,1,1) + sec

    print("DAYS:HOURS:MIN:SEC")
    print("%d:%d:%d:%d" % (d.day-1, d.hour, d.minute, d.second))