Python function to convert seconds into minutes, hours, and days

Question

Question: Write a program that asks the user to enter a number of seconds, and works as follows:

• There are 60 seconds in a minute. If the number of seconds

Answer 1

The "timeit" answer above that declares divmod to be slower has seriously flawed logic.

Test1 calls operators.

Test2 calls the function divmod, and calling a function has overhead.

A more accurate way to test would be:

import timeit

def moddiv(a,b):
  q= a/b
  r= a%b
  return q,r

a=10
b=3
md=0
dm=0
for i in range(1,10):
  c=a*i
  md+= timeit.timeit( lambda: moddiv(c,b))
  dm+=timeit.timeit( lambda: divmod(c,b))

print("moddiv ", md)
print("divmod ", dm)




moddiv  5.806157339000492

divmod  4.322451676005585

divmod is faster.

Answer 2

def convertSeconds(seconds):
    h = seconds//(60*60)
    m = (seconds-h*60*60)//60
    s = seconds-(h*60*60)-(m*60)
    return [h, m, s]

The function input is a number of seconds, and the return is a list of hours, minutes and seconds which that amount of seconds represent.

Answer 3

Although divmod() has been mentioned, I didn't see what I considered to be a nice example. Here's mine:

q=972021.0000  # For example
days = divmod(q, 86400) 
# days[0] = whole days and
# days[1] = seconds remaining after those days
hours = divmod(days[1], 3600)
minutes = divmod(hours[1], 60)
print "%i days, %i hours, %i minutes, %i seconds" % (days[0], hours[0], minutes[0], minutes[1])

Which outputs:

11 days, 6 hours, 0 minutes, 21 seconds

Answer 4

def seconds_to_dhms(time):
    seconds_to_minute   = 60
    seconds_to_hour     = 60 * seconds_to_minute
    seconds_to_day      = 24 * seconds_to_hour

    days    =   time // seconds_to_day
    time    %=  seconds_to_day

    hours   =   time // seconds_to_hour
    time    %=  seconds_to_hour

    minutes =   time // seconds_to_minute
    time    %=  seconds_to_minute

    seconds = time

    print("%d days, %d hours, %d minutes, %d seconds" % (days, hours, minutes, seconds))


time = int(input("Enter the number of seconds: "))
seconds_to_dhms(time)

Output: Enter the number of seconds: 2434234232

Result: 28174 days, 0 hours, 10 minutes, 32 seconds

Answer 5

This tidbit is useful for displaying elapsed time to varying degrees of granularity.

I personally think that questions of efficiency are practically meaningless here, so long as something grossly inefficient isn't being done. Premature optimization is the root of quite a bit of evil. This is fast enough that it'll never be your choke point.

intervals = (
    ('weeks', 604800),  # 60 * 60 * 24 * 7
    ('days', 86400),    # 60 * 60 * 24
    ('hours', 3600),    # 60 * 60
    ('minutes', 60),
    ('seconds', 1),
    )

def display_time(seconds, granularity=2):
    result = []

    for name, count in intervals:
        value = seconds // count
        if value:
            seconds -= value * count
            if value == 1:
                name = name.rstrip('s')
            result.append("{} {}".format(value, name))
    return ', '.join(result[:granularity])

..and this provides decent output:

In [52]: display_time(1934815)
Out[52]: '3 weeks, 1 day'

In [53]: display_time(1934815, 4)
Out[53]: '3 weeks, 1 day, 9 hours, 26 minutes'

Answer 6

def normalize_seconds(seconds: int) -> tuple:
    (days, remainder) = divmod(seconds, 86400)
    (hours, remainder) = divmod(remainder, 3600)
    (minutes, seconds) = divmod(remainder, 60)

    return namedtuple("_", ("days", "hours", "minutes", "seconds"))(days, hours, minutes, seconds)