I want to unwrap two optionals in one if statement, but the compiler complaints about an expected expression after operator at the password constant. What could be the reaso
Swift 4
if let suggestions = suggestions, let suggestions1 = suggestions1 {
XCTAssert((suggestions.count > suggestions1.count), "TEST CASE FAILED: suggestion is nil. delete sucessful");
}
The usage
if let x = y {
}
is not equivalent to
if (let x = y) { // this is actually not allowed
}
"if let" is effectively a two-word keyword, which is equivalent to
if y != nil {
let x = y!
// rest of if let block
}
How about wrapping the optionals in a tuple and using switch to pattern match?
switch (self.emailField?.text, self.passwordField?.text) {
case let (.Some(email), .Some(password)):
// unwrapped 'email' and 'password' strings available here
default:
break
}
It's definitely a bit noisier, but at least it could also be combined with a where clause as well.
Update for Swift 3:
if let email = emailField?.text, let password = passwordField?.text {
}
each variable must now be preceded by a let keyword
Before Swift 1.2
Like @James, I've also created an unwrap
function, but this one uses the existing if let
for control flow, instead of using a closure:
func unwrap<T1, T2>(optional1: T1?, optional2: T2?) -> (T1, T2)? {
switch (optional1, optional2) {
case let (.Some(value1), .Some(value2)):
return (value1, value2)
default:
return nil
}
}
This can be used like so:
if let (email, password) = unwrap(self.emailField?.text, self.passwordField?.text)
{
// do something
}
From: https://gist.github.com/tomlokhorst/f9a826bf24d16cb5f6a3
Note that if you want to handle more cases (like when one of the two fields is nil), you're better off with a switch
statement.
I can't explain why the above code doesn't work, but this would be good a replacement:
if let email = self.emailField?.text
{
if let password = self.passwordField?.text
{
//do smthg
}
}