Remove all falsy values from an array

Question

I would like to remove all falsy values from an array. Falsy values in JavaScript are false, null, 0, \"\", undefined, and NaN.

Answer 1

function bouncer(arr) {

// Don't show a false ID to this bouncer.

for (var i = 0; i < arr.length; i++) {
        if (!arr[i]) {
            arr.splice(i, 1);
            i = i-1;
        }
    }
    return arr;

}

bouncer([7, "ate", "", false, 9]);

Answer 2

Thanks for all working answers above. Here are 3 approaches to solve the problem. Third solution addressed problem by your approach @Vignesh.

1. 
function bouncer(arr) {
  return arr.filter( function( val ){
        return val;
    });
}

2. 
function bouncer(arr) {
return arr.filter(Boolean);
}
3.
  function bouncer(arr) {
  return arr.filter(function(val){
      return val !== false && val !== "" && !(Number.isNaN(val)) && val !== 
undefined && val !== 0 && val !== null;
    });
 }

Answer 3

Using filter we can write

function bouncer(arr) {
 return arr.filter(item => item);
}
bouncer([false, null, 0, NaN, undefined, ""]) // will return [].

Answer 4

function falsy(value) {
      if (value) {
        return value;
      }
    }

    function bouncer(arr) {
      var filter = arr.filter(falsy);
      return filter;
    }

    bouncer([7, "ate", "", false, 9]);