Remove all falsy values from an array

Question

I would like to remove all falsy values from an array. Falsy values in JavaScript are false, null, 0, \"\", undefined, and NaN.

Answer 1

I see you never accepted an answer. Is the problem that you are relying on Logger.log or console.log to see if the null removal worked? I think the filter suggested by @LoremIpsum is the cleanest solution.

  const src2DArr = [[34], [75], [30], [48], [976], [], [178], [473], [51], [75], [29], [47], [40]];
  Logger.log("src2DArr: " +JSON.stringify(src2DArr)); 
  // [[34],[75],[30],[48],[976],[],[178],[473],[51],[75],[29],[47],[40]]
  
  var src2DArr1 = src2DArr.filter(Boolean);
  Logger.log("src2DArr1: " + JSON.stringify(src2DArr1));
  // [[34],[75],[30],[48],[976],[],[178],[473],[51],[75],[29],[47],[40]] 

Answer 2

Just negate twice to "cast" to boolean. !NaN === true => !!NaN === false

    const truthy = arr.filter(o => !!o)

Answer 3

You can use Boolean :

var myFilterArray = myArray.filter(Boolean);

Answer 4

bouncer function:

function bouncer(arr) {
  return arr.filter((val) => {
    return !!val;
  });
}

console.log(bouncer([7, "ate", "", false, 9]));

Answer 5

myArray = [false, null, 0, NaN, undefined, ""];
myArray.map(item => {
//if you want you can write logic
        console.log(item);
    })
    // Get rid of bad values
    .filter(Boolean);

it will return [].

Answer 6

I think a better deal this way

   function bouncer(arr) {
        arr = arr.filter(function(item) {
            return item;
        return arr;

    bouncer([7, "ate", "", false, 9, NaN, undefined, 0]);