Remove all falsy values from an array

Question

I would like to remove all falsy values from an array. Falsy values in JavaScript are false, null, 0, \"\", undefined, and NaN.

Answer 1

This is my idea...

function bouncer(arr) {
  // Don't show a false ID to this bouncer.
  var result = [];
  
    function isGood(obj){
      if(!Boolean(obj)){
        return false;
      } else {
        return true;
      }
    }
    
    for (var i=0; i < arr.length; i++){
      if (isGood(arr[i]) === true){
        result.push(arr[i]);
      }
    }
  return result;
}

console.log(bouncer([7, "ate", "", false, 9]));

Answer 2

function bouncer(arr) {  
  var result = []; 
   for (var i = 0; i < arr.length; i++) {
     if (arr[i]) {
      result.push(arr[i]);
     }
   }
  return result;
 }

 bouncer([7, "ate", "", false, 9]);

Answer 3

Using this simple filter will do:

array.filter(Boolean)

You can read more about Boolean here

Answer 4

This should be what you are looking for:

let array = [7, 'ate', '', false, 9, NaN];

function removeFalsyItems(array) {
   // Your result
   let filter = array.filter(Boolean);

   // Empty the array
   array.splice(0, array.length);

   // Push all items from the result to our array
   Array.prototype.push.apply(array, filter);

   return array
}

removeFalsyItems(array) // => [7, 'ate', 9], funny joke btw...

Answer 5

Try using filter and Boolean:

let array = [7,"ate","",false,9];
array.filter((values) => {return Boolean(values) === true })

Answer 6

function bouncer(arr) {

    function filterFalse(value) {
        var a = Boolean(value);
        if (a === true) {
            return a;
        }
        return a;
    }

    function filterArray(x) {
        var y = filterFalse(x);
        if (y) {
            return true;
        } else {
            return false;
        }
    }

    var newArr = arr.filter(filterArray);
    return newArr;
}

bouncer([1, null, NaN, 2, undefined]);