Calling a generic method with a dynamic type [duplicate]

Answer 1

Try this:

public List<T> CreateAnimals<T>(int numAnimals) where T : Animal
{
    Type type = typeof(T);
    List<T> returnList = new List<T>();
    //Use reflection to populate list and return
}

It should make sure that the allowed types for CreateAnimals inherit from Animal. Then hopefully, it won't have a problem with List<animalType> animals = creator.CreateAnimals<type>(5);

Answer 2

The keys to this are MakeGenericType() and MakeGenericMethod(). Once you've gone dynamic with the types, you can't really go back to static typing. What you CAN do is create the list dynamically, by using Activator.CreateInstance(typeof(List<>).MakeGenericType(type)) and then dynamically calling the generic method using similar reflective methods.

Answer 3

List<animalType> animals = 
 creator.CreateAnimals<type>(5);

In the above line from your example, animalType and type are run time variables, not types, so this is of course nonsense. A generic version only makes sense, if you know the types at compile time, e.g.:

List<Animal> animals = 
  creator.CreateAnimals<Cow>(5);

where you'd have to constraint types accordingly. If the types are not known, you have to rely completely on reflection...

Answer 4

I don't know about elegant, but the way to do it is:

typeof(Creator)
    .GetMethod("CreateAnimals")
    .MakeGenericMethod(type)
    .Invoke(creator, new object[] { 5 });

Answer 5

Not really. You need to use reflection, basically. Generics are really aimed at static typing rather than types only known at execution time.

To use reflection, you'd use Type.GetMethod to get the method definition, then call MethodInfo.MakeGenericMethod(type), then invoke it like any other method.