Subtract 1 day with PHP

Question

I\'m trying to take a date object that\'s coming out of my Drupal CMS, subtract one day and print out both dates. Here\'s what I have

$date_raw = $messageno         


        

Answer 1

How about this: convert it to a unix timestamp first, subtract 60*60*24 (exactly one day in seconds), and then grab the date from that.

$newDate = strtotime($date_raw) - 60*60*24;
echo date('Y-m-d',$newDate);

Note: as apokryfos has pointed out, this would technically be thrown off by daylight savings time changes where there would be a day with either 25 or 23 hours

Answer 2

Simple like that:

date("Y-m-d", strtotime("-1 day"));

date("Y-m-d", strtotime("-1 months"))

Answer 3

$date = new DateTime("2017-05-18"); // For today/now, don't pass an arg.
$date->modify("-1 day");
echo $date->format("Y-m-d H:i:s");

Using DateTime has significantly reduced the amount of headaches endured whilst manipulating dates.

Answer 4

Not sure why your current code isn't working but if you don't specifically need a date object this will work:

$first_date = strtotime($date_raw);
$second_date = strtotime('-1 day', $first_date);

print 'First Date ' . date('Y-m-d', $first_date);
print 'Next Date ' . date('Y-m-d', $second_date);

Answer 5

Object oriented version

$dateObject = new DateTime( $date_raw );
print('Next Date ' . $dateObject->sub( new DateInterval('P1D') )->format('Y-m-d');

Answer 6

You can try:

print('Next Date ' . date('Y-m-d', strtotime('-1 day', strtotime($date_raw))));