ArrayList
With Java Generics Takes a list of X and returns a list of T that extends or implements X, Sweet!
// the cast is is actually checked via the method API
@SuppressWarnings("unchecked")
public static <T extends X, X> ArrayList<T> convertToClazz(ArrayList<X> from, Class<X> inClazz, Class<T> outClazz) {
ArrayList<T> to = new ArrayList<T>();
for (X data : from) {
to.add((T) data);
}
return to;
}
Since this is actually not a list of strings, the easiest way is to loop over it and convert each item into a new list of strings yourself:
List<String> strings = list.stream()
.map(object -> Objects.toString(object, null))
.collect(Collectors.toList());
Or when you're not on Java 8 yet:
List<String> strings = new ArrayList<>(list.size());
for (Object object : list) {
strings.add(Objects.toString(object, null));
}
Or when you're not on Java 7 yet:
List<String> strings = new ArrayList<String>(list.size());
for (Object object : list) {
strings.add(object != null ? object.toString() : null);
}
Note that you should be declaring against the interface (java.util.List in this case), not the implementation.
It's not safe to do that!
Imagine if you had:
ArrayList<Object> list = new ArrayList<Object>();
list.add(new Employee("Jonh"));
list.add(new Car("BMW","M3"));
list.add(new Chocolate("Twix"));
It wouldn't make sense to convert the list of those Objects to any type.
If you want to do it the dirty way, try this.
@SuppressWarnings("unchecked")
public ArrayList<String> convert(ArrayList<Object> a) {
return (ArrayList) a;
}
Advantage: here you save time by not iterating over all objects.
Disadvantage: may produce a hole in your foot.
Here is another alternative using Guava
List<Object> lst ...
List<String> ls = Lists.transform(lst, Functions.toStringFunction());
Using Java 8 lambda:
ArrayList<Object> obj = new ArrayList<>();
obj.add(1);
obj.add("Java");
obj.add(3.14);
ArrayList<String> list = new ArrayList<>();
obj.forEach((xx) -> list.add(String.valueOf(xx)));