Java: Check if command line arguments are null

Question

I am looking to do some error checking for my command line arguments

public static void main(String[] args)
{
    if(args[0] == null)
    {
        System.ou         


        

Answer 1

@jjnguy's answer is correct in most circumstances. You won't ever see a null String in the argument array (or a null array) if main is called by running the application is run from the command line in the normal way.

However, if some other part of the application calls a main method, it is conceivable that it might pass a null argument or null argument array.

However(2), this is clearly a highly unusual use-case, and it is an egregious violation of the implied contract for a main entry-point method. Therefore, I don't think you should bother checking for null argument values in main. In the unlikely event that they do occur, it is acceptable for the calling code to get a NullPointerException. After all, it is a bug in the caller to violate the contract.

Answer 2

To expand upon this point:

It is possible that the args variable itself will be null, but not via normal execution. Normal execution will use java.exe as the entry point from the command line. However, I have seen some programs that use compiled C++ code with JNI to use the jvm.dll, bypassing the java.exe entirely. In this case, it is possible to pass NULL to the main method, in which case args will be null.

I recommend always checking if ((args == null) || (args.length == 0)), or if ((args != null) && (args.length > 0)) depending on your need.

Answer 3

if i want to check if any speicfic position of command line arguement is passed or not then how to check? like for example in some scenarios 2 command line args will be passed and in some only one will be passed then how do it check wheather the specfic commnad line is passed or not?

public class check {

public static void main(String[] args) {
if(args[0].length()!=0)
{
System.out.println("entered first if");
}
if(args[0].length()!=0 && args[1].length()!=0)
{
System.out.println("entered second if");
}
}
}

So in the above code if args[1] is not passed then i get java.lang.ArrayIndexOutOfBoundsException:

so how do i tackle this where i can check if second arguement is passed or not and if passed then enter it. need assistance asap.

Answer 4

You should check for (args == null || args.length == 0). Although the null check isn't really needed, it is a good practice.

Answer 5

The arguments can never be null. They just wont exist.

In other words, what you need to do is check the length of your arguments.

public static void main(String[] args)
{
    // Check how many arguments were passed in
    if(args.length == 0)
    {
        System.out.println("Proper Usage is: java program filename");
        System.exit(0);
    }
}

Answer 6

If you don't pass any argument then even in that case args gets initialized but without any item/element. Try the following one, you will get the same effect:

 
public static void main(String[] args) throws InterruptedException {
        String [] dummy= new String [] {};
        if(dummy[0] == null)
        {
            System.out.println("Proper Usage is: java program filename");
            System.exit(0);
        }

    }