I know what user is logged in with the following line of code:
Session[\"loggedInUserId\"] = userId;
The question I have is how do I know w
I didn't try rangitatanz solution, but I used another method and it worked just fine for me.
private List<String> getOnlineUsers()
{
List<String> activeSessions = new List<String>();
object obj = typeof(HttpRuntime).GetProperty("CacheInternal", BindingFlags.NonPublic | BindingFlags.Static).GetValue(null, null);
object[] obj2 = (object[])obj.GetType().GetField("_caches", BindingFlags.NonPublic | BindingFlags.Instance).GetValue(obj);
for (int i = 0; i < obj2.Length; i++)
{
Hashtable c2 = (Hashtable)obj2[i].GetType().GetField("_entries", BindingFlags.NonPublic | BindingFlags.Instance).GetValue(obj2[i]);
foreach (DictionaryEntry entry in c2)
{
object o1 = entry.Value.GetType().GetProperty("Value", BindingFlags.NonPublic | BindingFlags.Instance).GetValue(entry.Value, null);
if (o1.GetType().ToString() == "System.Web.SessionState.InProcSessionState")
{
SessionStateItemCollection sess = (SessionStateItemCollection)o1.GetType().GetField("_sessionItems", BindingFlags.NonPublic | BindingFlags.Instance).GetValue(o1);
if (sess != null)
{
if (sess["loggedInUserId"] != null)
{
activeSessions.Add(sess["loggedInUserId"].ToString());
}
}
}
}
}
return activeSessions;
}
There is a solution listed in this page List all active ASP.NET Sessions
private static List<string> _sessionInfo;
private static readonly object padlock = new object();
public static List<string> Sessions
{
get
{
lock (padlock)
{
if (_sessionInfo == null)
{
_sessionInfo = new List<string>();
}
return _sessionInfo;
}
}
}
protected void Session_Start(object sender, EventArgs e)
{
Sessions.Add(Session.SessionID);
}
protected void Session_End(object sender, EventArgs e)
{
Sessions.Remove(Session.SessionID);
}
Basically it just tracks sessions into a List that you can use to find out information about. Can really store anything into that that you really want to - Usernames or whatever.
I don't htink there is anything at the ASP .net layer that does this already?