Python: give start and end of week data from a given date

Question

day = \"13/Oct/2013\"
print(\"Parsing :\",day)
day, mon, yr= day.split(\"/\")
sday = yr+\" \"+day+\" \"+mon
myday = time.strptime(sday, \'%Y %d %b\')
Sstart = yr+\"          


        

Answer 1

Use the pendulum module:

today = pendulum.now()
start = today.start_of('week')
end = today.end_of('week')

Answer 2

Use the datetime module.

This will yield start and end of week (from Monday to Sunday):

from datetime import datetime, timedelta

day = '12/Oct/2013'
dt = datetime.strptime(day, '%d/%b/%Y')
start = dt - timedelta(days=dt.weekday())
end = start + timedelta(days=6)
print(start)
print(end)

EDIT:

print(start.strftime('%d/%b/%Y'))
print(end.strftime('%d/%b/%Y'))

Answer 3

Slight variation if you want to keep the standard time formatting and refer to the current day:

from datetime import datetime, timedelta

today = datetime.now().date()
start = today - timedelta(days=today.weekday())
end = start + timedelta(days=6)
print("Today: " + str(today))
print("Start: " + str(start))
print("End: " + str(end))