If I use malloc
in my code:
int *x = malloc(sizeof(int));
I get this warning from gcc
:
new.c:7: w
You need to include the header file that declares the function, for example:
#include <stdlib.h>
If you don't include this header file, the function is not known to the compiler. So it sees it as undeclared.
You need to add:
#include <stdlib.h>
This file includes the declaration for the built-in function malloc
. If you don't do that, the compiler thinks you want to define your own function named malloc
and it warns you because:
int
, which isn't compatible with the built-in malloc
, which takes a size_t
and returns a void*
).Beside the other very good answers, I would like to do a little nitpick and cover something what is not discussed yet in the other answers.
When you are at Linux, To use malloc()
in your code,
You don´t actually have to #include <stdlib.h>
.
(Although the use of stdlib.h
is very common and probably every non-toy-program should include it either way because it provides a wide range of useful C standard library functions and macros)
You could also #include <malloc.h>
instead.
But please note that the use of malloc.h
is deprecated and it makes your code non-portable. If you want to use malloc()
you should always and ever (except for explicit reasons to do otherwise) #include <stdlib.h>
.
The reasons why, are best explained in the answers to this question:
difference between <stdlib.h> and <malloc.h>
You haven't done #include <stdlib.h>
.
Make a habit of looking your functions up in help.
Most help for C is modelled on the unix manual pages.
Using :
man malloc
gives pretty useful results.
Googling man malloc
will show you what I mean.
In unix you also get apropos for things that are related.