If you do not want to use an external component, here is some code I developed last night using .NET's ZipPackage class.
private static void Unzip()
{
var zipFilePath = "c:\\myfile.zip";
var tempFolderPath = "c:\\unzipped";
using (Package pkg = ZipPackage.Open(zipFilePath, FileMode.Open, FileAccess.Read))
{
foreach (PackagePart part in pkg.GetParts())
{
var target = Path.GetFullPath(Path.Combine(tempFolderPath, part.Uri.OriginalString.TrimStart('/')));
var targetDir = target.Remove(target.LastIndexOf('\\'));
if (!Directory.Exists(targetDir))
Directory.CreateDirectory(targetDir);
using (Stream source = part.GetStream(FileMode.Open, FileAccess.Read))
{
CopyStream(source, File.OpenWrite(target));
}
}
}
}
private static void CopyStream(Stream input, Stream output)
{
byte[] buffer = new byte[4096];
int read;
while ((read = input.Read(buffer, 0, buffer.Length)) > 0)
{
output.Write(buffer, 0, read);
}
}
Things to note:
The ZIP archive MUST have a [Content_Types].xml file in its root. This was a non-issue for my requirements as I will control the zipping of any ZIP files that get extracted through this code. For more information on the [Content_Types].xml file, please refer to: http://msdn.microsoft.com/en-us/magazine/cc163372.aspx There is an example file below Figure 13 of the article.
I have not tested the CopyStream method to ensure it behaves correctly, as I originally developed this for .NET 4.0 using the Stream.CopyTo() method.
