How to sort a List<Object> alphabetically using Object name field

Answer 1

if(listAxu.size() > 0){
     Collections.sort(listAxu, new Comparator<Situacao>(){
        @Override
        public int compare(Situacao lhs, Situacao rhs) {            
            return lhs.getDescricao().compareTo(rhs.getDescricao());
        }
    });
 }

Answer 2

The most correct way to sort alphabetically strings is to use Collator, because of internationalization. Some languages have different order due to few extra characters etc.

   Collator collator = Collator.getInstance(Locale.US);
   if (!list.isEmpty()) {
    Collections.sort(list, new Comparator<Campaign>() {
        @Override
        public int compare(Campaign c1, Campaign c2) {
            //You should ensure that list doesn't contain null values!
            return collator.compare(c1.getName(), c2.getName());
        }
       });
   }

If you don't care about internationalization use string.compare(otherString).

   if (!list.isEmpty()) {
    Collections.sort(list, new Comparator<Campaign>() {
        @Override
        public int compare(Campaign c1, Campaign c2) {
            //You should ensure that list doesn't contain null values!
            return c1.getName().compare(c2.getName());
        }
       });
   }

Answer 3

If your objects has some common ancestor [let it be T] you should use List<T> instead of List<Object>, and implement a Comparator for this T, using the name field.

If you don't have a common ancestor, you can implement a Comperator, and use reflection to extract the name, Note that it is unsafe, unsuggested, and suffers from bad performance to use reflection, but it allows you to access a field name without knowing anything about the actual type of the object [besides the fact that it has a field with the relevant name]

In both cases, you should use Collections.sort() to sort.

Answer 4

I found another way to do the type.

if(listAxu.size() > 0){
    Collections.sort(listAxu, Comparator.comparing(IdentityNamed::getDescricao));
}

Answer 5

something like

  List<FancyObject> theList = … ;
  Collections.sort (theList,
                    new Comparator<FancyObject> ()
                    { int compare (final FancyObject a, final FancyObject d)
                          { return (a.getName().compareTo(d.getName())); }});

Answer 6

Using Java 8 Comparator.comparing:

list.sort(Comparator.comparing(Campaign::getName));