You've hit on a couple different things here, but I'll try to hit your main question first.
In general....
function() { ... } is a function expression. Syntaxically this is on the same level as 2 or [4,5]. This represents a value. So doing var foo=function(){ ... } will work as planned, every time.
function foo() { ... } is a function declaration. This might seem to do the same thing as var foo=function(){...}, but there's a small caveat. As its a declaration, it works similar to the concept of variable hoisting in JS (basically, all variable declarations are done before any expressions are evaluated).
A good example is from here:
function test() {
foo(); // TypeError "foo is not a function"
bar(); // "this will run!"
var foo = function () { // function expression assigned to local variable 'foo'
alert("this won't run!");
}
function bar() { // function declaration, given the name 'bar'
alert("this will run!");
}
}
test();
Basically variable hoisting has brought the value up to the top, so this code is equivalent (in theory) to :
function test() {
var foo;//foo hoisted to top
var bar=function(){//this as well
alert("this will run!");
}
foo(); // TypeError "foo is not a function"
bar(); // "this will run!"
var foo = function () { // function expression assigned to local variable 'foo'
alert("this won't run!");
}
}
NB: I'd like to take this spot to say that JS interpreters have a hard time following theory, so trusting them on somewhat iffy behaviour is not recommended. Here you'll find a good example at the end of a section where theory and practice end up not working (there are also some more details on the topic of expressions vs declarations).
Fun fact: wrapping function foo() {...} in parentheses transforms it from a declaration to an expression, which can lead to some weird looking code like
(function foo() { return 1; })();// 1
foo; //ReferenceError: foo is not defined
Don't do this if you don't have a reason to, please.
Summary var foo=function(){ ... } is *sorta kinda * the same as function foo(){ ... } except that the former does what you think it does where you think it should whereas the latter does weird stuff unless you wrap it in parens, but that messes up the scope, and JS interpreters allow you to do things that are considered syntax errors in the spec so you're led to believe that wrong things are in fact right, etc....
please use function expressions( var f=function(){...} ). There's no real reason not to, especially considering you're somewhat forced to do it when you're using dot syntax.
On to the second thing you touched.....
I'm not really sure what to say, it's kinda sorta completely different from everything else about this.
var foo = {
baz: 43,
doSomething:function() {
...
}
}
this is known as object literal syntax. JSON, which is based off of this syntax, is a pretty neat way of formatting data, and this syntax in JS is often used to declare new objects, with singleton objects for example(avoiding all the mess with declaring a function and using new ). It can also be used in the same way XML is used, and is preferred by all the cool kids...
Anyways, basically object literal syntax works like this:
{ name1: val1, .... namek:valk }
This expression is an object with certain values initialised on it. so doing var obj={ name1: val1, .... namek:valk } means that :
obj.name1==val1;
obj['name1']==val1;// x['y'] is the same thing as x.y
...
obj.namek==valk;
So what does this have to do with our example? Basically your expression is often used to declare singleton objects. But it can also be used to declare an object prototype, so someone can later do var newObj=Object.create(foo) , and newObj will have foo as a prototype.
Look into prototypal inheritence in detail if you want to really get how useful it is. Douglas Crockford talks about it in detail in one of his many talks).
