In C#, is there a way to instantiate an instance of a class without invoking its constructor?
Assume the class is public and is defined in a 3rd par
Contrary to what many believe, a constructor hasn't much to do with the instantiation of an object at all (pretty misleading term). A constructor is a special method that can be called after the instantiation of an object to allow that object to properly initialize itself. In C++ object instantiation allocates memory for the object, in .NET and Java it is both allocated and pre-initialized to default values depending on the type of fields (0, null, false etc.). Then the run-time calls the constructor. The new operator encapsulates these two separate actions into what appears to be a single operation. Deserialization could never had worked in .NET if it wasn't possible to create an instance without using a constructor. That said, the so called ConstructorInfo type acts as both a new operator and constructor when calling its Invoke(...) method.
EDIT: You updated your question, you want to construct a class without a constructor. Or call a default "Empty Constructor".
This cannot be done, as the compiler will not generate a default constructor if there is already one specified. However, for the benefit of the readers, here is how to get at a internal, protected, or private constructor:
Assuming your class is called Foo:
using System.Reflection;
// If the constructor takes arguments, otherwise pass these as null
Type[] pTypes = new Type[1];
pTypes[0] = typeof(object);
object[] argList = new object[1];
argList[0] = constructorArgs;
ConstructorInfo c = typeof(Foo).GetConstructor
(BindingFlags.NonPublic |
BindingFlags.Instance,
null,
pTypes,
null);
Foo foo =
(Foo) c.Invoke(BindingFlags.NonPublic,
null,
argList,
Application.CurrentCulture);
Ugly, but works.
Of course, there may be a perfectly legitimate reason to mark a constructor as internal, so you should really consider the logistics of what you want before you abuse that class by getting at it with reflection.
If the class (and the classes of objects that it references) is Serializable, you can create a deep copy by serializing using a BinaryFormatter that outputs to a MemoryStream (creating a byte array byte[]), then deserializing. See the answers to this question on converting an object to a byte array. (But note - saving the byte array to use later/elsewhere is likely not to work. IOW don't save the byte array to a file or other persistent form.)
Actually it sounds like they made the constructor internal just so you can't instantiate it. It may have a builder or factory method.
Check out these articles:
Preventing Third Party Derivation: Part 1
Preventing Third Party Derivation: Part 2
they kind of explain the reasoning.
I noticed the "deadness" of the subject but just for clarification on further readers and to put a final answer that maybe wasn't possible when the question was posted. Here it goes.
It seems that you can instantiate a class without using it's constructors by assigning values to its properties. Here is the address where is the how-to in MSDN for this type of instantiation http://msdn.microsoft.com/en-us/library/bb397680.aspx.
It seems like this is a technique that's not well known because I encountered it in a article in CodeProject and then googled it and didn't find anything about it and later on visited the MSDN Homepage and there was a post that linked me to that exact subject. So it seems that it's an unknown subject rather than a new one because the date on the CodeProject post dates May 2008.
Hope this helps someone else that google's this and comes across with this question.
You have to call a constructor to create an object. If there are none available to your liking perhaps you could use a byte code rewriting library like the Mono project's Cecil. It works on Windows as well as Linux. From some of the demos I saw, it looked pretty cool. You can change the protection levels of methods and all sorts of crazy stuff.