MySQL Great Circle Distance (Haversine formula)

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栀梦
栀梦 2020-11-21 06:53

I\'ve got a working PHP script that gets Longitude and Latitude values and then inputs them into a MySQL query. I\'d like to make it solely MySQL. Here\'s my current PHP Cod

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  • 2020-11-21 07:12

    I can't comment on the above answer, but be careful with @Pavel Chuchuva's answer. That formula will not return a result if both coordinates are the same. In that case, distance is null, and so that row won't be returned with that formula as is.

    I'm not a MySQL expert, but this seems to be working for me:

    SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance 
    FROM markers HAVING distance < 25 OR distance IS NULL ORDER BY distance LIMIT 0 , 20;
    
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  • 2020-11-21 07:15

    I have had to work this out in some detail, so I'll share my result. This uses a zip table with latitude and longitude tables. It doesn't depend on Google Maps; rather you can adapt it to any table containing lat/long.

    SELECT zip, primary_city, 
           latitude, longitude, distance_in_mi
      FROM (
    SELECT zip, primary_city, latitude, longitude,r,
           (3963.17 * ACOS(COS(RADIANS(latpoint)) 
                     * COS(RADIANS(latitude)) 
                     * COS(RADIANS(longpoint) - RADIANS(longitude)) 
                     + SIN(RADIANS(latpoint)) 
                     * SIN(RADIANS(latitude)))) AS distance_in_mi
     FROM zip
     JOIN (
            SELECT  42.81  AS latpoint,  -70.81 AS longpoint, 50.0 AS r
       ) AS p 
     WHERE latitude  
      BETWEEN latpoint  - (r / 69) 
          AND latpoint  + (r / 69)
       AND longitude 
      BETWEEN longpoint - (r / (69 * COS(RADIANS(latpoint))))
          AND longpoint + (r / (69 * COS(RADIANS(latpoint))))
      ) d
     WHERE distance_in_mi <= r
     ORDER BY distance_in_mi
     LIMIT 30
    

    Look at this line in the middle of that query:

        SELECT  42.81  AS latpoint,  -70.81 AS longpoint, 50.0 AS r
    

    This searches for the 30 nearest entries in the zip table within 50.0 miles of the lat/long point 42.81/-70.81 . When you build this into an app, that's where you put your own point and search radius.

    If you want to work in kilometers rather than miles, change 69 to 111.045 and change 3963.17 to 6378.10 in the query.

    Here's a detailed writeup. I hope it helps somebody. http://www.plumislandmedia.net/mysql/haversine-mysql-nearest-loc/

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  • 2020-11-21 07:20

    From Google Code FAQ - Creating a Store Locator with PHP, MySQL & Google Maps:

    Here's the SQL statement that will find the closest 20 locations that are within a radius of 25 miles to the 37, -122 coordinate. It calculates the distance based on the latitude/longitude of that row and the target latitude/longitude, and then asks for only rows where the distance value is less than 25, orders the whole query by distance, and limits it to 20 results. To search by kilometers instead of miles, replace 3959 with 6371.

    SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) 
    * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin(radians(lat)) ) ) AS distance 
    FROM markers 
    HAVING distance < 25 
    ORDER BY distance 
    LIMIT 0 , 20;
    
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