Remove part of string in Java

Question

I want to remove a part of string from one character, that is:

Source string:

manchester united (with nice players)

Target string:

Answer 1

String Replace

String s = "manchester united (with nice players)";
s = s.replace(" (with nice players)", "");

Edit:

By Index

s = s.substring(0, s.indexOf("(") - 1);

Answer 2

I would at first split the original string into an array of String with a token " (" and the String at position 0 of the output array is what you would like to have.

String[] output = originalString.split(" (");

String result = output[0];

Answer 3

originalString.replaceFirst("[(].*?[)]", "");

https://ideone.com/jsZhSC
replaceFirst() can be replaced by replaceAll()

Answer 4

You could use replace to fix your string. The following will return everything before a "(" and also strip all leading and trailing whitespace. If the string starts with a "(" it will just leave it as is.

str = "manchester united (with nice players)"
matched = str.match(/.*(?=\()/)
str.replace(matched[0].strip) if matched

Answer 5

// Java program to remove a substring from a string
public class RemoveSubString {

    public static void main(String[] args) {
        String master = "1,2,3,4,5";
        String to_remove="3,";

        String new_string = master.replace(to_remove, "");
        // the above line replaces the t_remove string with blank string in master

        System.out.println(master);
        System.out.println(new_string);

    }
}

Answer 6

If you just need to remove everything after the "(", try this. Does nothing if no parentheses.

StringUtils.substringBefore(str, "(");

If there may be content after the end parentheses, try this.

String toRemove = StringUtils.substringBetween(str, "(", ")");
String result = StringUtils.remove(str, "(" + toRemove + ")"); 

To remove end spaces, use str.trim()

Apache StringUtils functions are null-, empty-, and no match- safe