I\'m trying to write a function that does the following:
The following very efficient algorithm uses Heap's method to generate all permutations of N elements with runtime complexity in O(N!):
function permute(permutation) {
var length = permutation.length,
result = [permutation.slice()],
c = new Array(length).fill(0),
i = 1, k, p;
while (i < length) {
if (c[i] < i) {
k = i % 2 && c[i];
p = permutation[i];
permutation[i] = permutation[k];
permutation[k] = p;
++c[i];
i = 1;
result.push(permutation.slice());
} else {
c[i] = 0;
++i;
}
}
return result;
}
console.log(permute([1, 2, 3]));
The same algorithm implemented as a generator with space complexity in O(N):
function* permute(permutation) {
var length = permutation.length,
c = Array(length).fill(0),
i = 1, k, p;
yield permutation.slice();
while (i < length) {
if (c[i] < i) {
k = i % 2 && c[i];
p = permutation[i];
permutation[i] = permutation[k];
permutation[k] = p;
++c[i];
i = 1;
yield permutation.slice();
} else {
c[i] = 0;
++i;
}
}
}
// Memory efficient iteration through permutations:
for (var permutation of permute([1, 2, 3])) console.log(permutation);
// Simple array conversion:
var permutations = [...permute([1, 2, 3])];
Feel free to add your implementation to the following benchmark.js test suite:
function permute_SiGanteng(input) {
var permArr = [],
usedChars = [];
function permute(input) {
var i, ch;
for (i = 0; i < input.length; i++) {
ch = input.splice(i, 1)[0];
usedChars.push(ch);
if (input.length == 0) {
permArr.push(usedChars.slice());
}
permute(input);
input.splice(i, 0, ch);
usedChars.pop();
}
return permArr
}
return permute(input);
}
function permute_delimited(inputArr) {
var results = [];
function permute(arr, memo) {
var cur, memo = memo || [];
for (var i = 0; i < arr.length; i++) {
cur = arr.splice(i, 1);
if (arr.length === 0) {
results.push(memo.concat(cur));
}
permute(arr.slice(), memo.concat(cur));
arr.splice(i, 0, cur[0]);
}
return results;
}
return permute(inputArr);
}
function permute_monkey(inputArray) {
return inputArray.reduce(function permute(res, item, key, arr) {
return res.concat(arr.length > 1 && arr.slice(0, key).concat(arr.slice(key + 1)).reduce(permute, []).map(function(perm) {
return [item].concat(perm);
}) || item);
}, []);
}
function permute_Oriol(input) {
var permArr = [],
usedChars = [];
return (function main() {
for (var i = 0; i < input.length; i++) {
var ch = input.splice(i, 1)[0];
usedChars.push(ch);
if (input.length == 0) {
permArr.push(usedChars.slice());
}
main();
input.splice(i, 0, ch);
usedChars.pop();
}
return permArr;
})();
}
function permute_MarkusT(input) {
function permutate(array, callback) {
function p(array, index, callback) {
function swap(a, i1, i2) {
var t = a[i1];
a[i1] = a[i2];
a[i2] = t;
}
if (index == array.length - 1) {
callback(array);
return 1;
} else {
var count = p(array, index + 1, callback);
for (var i = index + 1; i < array.length; i++) {
swap(array, i, index);
count += p(array, index + 1, callback);
swap(array, i, index);
}
return count;
}
}
if (!array || array.length == 0) {
return 0;
}
return p(array, 0, callback);
}
var result = [];
permutate(input, function(a) {
result.push(a.slice(0));
});
return result;
}
function permute_le_m(permutation) {
var length = permutation.length,
result = [permutation.slice()],
c = new Array(length).fill(0),
i = 1, k, p;
while (i < length) {
if (c[i] < i) {
k = i % 2 && c[i],
p = permutation[i];
permutation[i] = permutation[k];
permutation[k] = p;
++c[i];
i = 1;
result.push(permutation.slice());
} else {
c[i] = 0;
++i;
}
}
return result;
}
function permute_Urielzen(arr) {
var finalArr = [];
var iterator = function (arrayTaken, tree) {
for (var i = 0; i < tree; i++) {
var temp = arrayTaken.slice();
temp.splice(tree - 1 - i, 0, temp.splice(tree - 1, 1)[0]);
if (tree >= arr.length) {
finalArr.push(temp);
} else { iterator(temp, tree + 1); }
}
}
iterator(arr, 1); return finalArr;
}
function permute_Taylor_Hakes(arr) {
var permutations = [];
if (arr.length === 1) {
return [ arr ];
}
for (var i = 0; i < arr.length; i++) {
var subPerms = permute_Taylor_Hakes(arr.slice(0, i).concat(arr.slice(i + 1)));
for (var j = 0; j < subPerms.length; j++) {
subPerms[j].unshift(arr[i]);
permutations.push(subPerms[j]);
}
}
return permutations;
}
var Combinatorics = (function () {
'use strict';
var version = "0.5.2";
/* combinatory arithmetics */
var P = function(m, n) {
var p = 1;
while (n--) p *= m--;
return p;
};
var C = function(m, n) {
if (n > m) {
return 0;
}
return P(m, n) / P(n, n);
};
var factorial = function(n) {
return P(n, n);
};
var factoradic = function(n, d) {
var f = 1;
if (!d) {
for (d = 1; f < n; f *= ++d);
if (f > n) f /= d--;
} else {
f = factorial(d);
}
var result = [0];
for (; d; f /= d--) {
result[d] = Math.floor(n / f);
n %= f;
}
return result;
};
/* common methods */
var addProperties = function(dst, src) {
Object.keys(src).forEach(function(p) {
Object.defineProperty(dst, p, {
value: src[p],
configurable: p == 'next'
});
});
};
var hideProperty = function(o, p) {
Object.defineProperty(o, p, {
writable: true
});
};
var toArray = function(f) {
var e, result = [];
this.init();
while (e = this.next()) result.push(f ? f(e) : e);
this.init();
return result;
};
var common = {
toArray: toArray,
map: toArray,
forEach: function(f) {
var e;
this.init();
while (e = this.next()) f(e);
this.init();
},
filter: function(f) {
var e, result = [];
this.init();
while (e = this.next()) if (f(e)) result.push(e);
this.init();
return result;
},
lazyMap: function(f) {
this._lazyMap = f;
return this;
},
lazyFilter: function(f) {
Object.defineProperty(this, 'next', {
writable: true
});
if (typeof f !== 'function') {
this.next = this._next;
} else {
if (typeof (this._next) !== 'function') {
this._next = this.next;
}
var _next = this._next.bind(this);
this.next = (function() {
var e;
while (e = _next()) {
if (f(e))
return e;
}
return e;
}).bind(this);
}
Object.defineProperty(this, 'next', {
writable: false
});
return this;
}
};
/* power set */
var power = function(ary, fun) {
var size = 1 << ary.length,
sizeOf = function() {
return size;
},
that = Object.create(ary.slice(), {
length: {
get: sizeOf
}
});
hideProperty(that, 'index');
addProperties(that, {
valueOf: sizeOf,
init: function() {
that.index = 0;
},
nth: function(n) {
if (n >= size) return;
var i = 0,
result = [];
for (; n; n >>>= 1, i++) if (n & 1) result.push(this[i]);
return (typeof (that._lazyMap) === 'function')?that._lazyMap(result):result;
},
next: function() {
return this.nth(this.index++);
}
});
addProperties(that, common);
that.init();
return (typeof (fun) === 'function') ? that.map(fun) : that;
};
/* combination */
var nextIndex = function(n) {
var smallest = n & -n,
ripple = n + smallest,
new_smallest = ripple & -ripple,
ones = ((new_smallest / smallest) >> 1) - 1;
return ripple | ones;
};
var combination = function(ary, nelem, fun) {
if (!nelem) nelem = ary.length;
if (nelem < 1) throw new RangeError;
if (nelem > ary.length) throw new RangeError;
var first = (1 << nelem) - 1,
size = C(ary.length, nelem),
maxIndex = 1 << ary.length,
sizeOf = function() {
return size;
},
that = Object.create(ary.slice(), {
length: {
get: sizeOf
}
});
hideProperty(that, 'index');
addProperties(that, {
valueOf: sizeOf,
init: function() {
this.index = first;
},
next: function() {
if (this.index >= maxIndex) return;
var i = 0,
n = this.index,
result = [];
for (; n; n >>>= 1, i++) {
if (n & 1) result[result.length] = this[i];
}
this.index = nextIndex(this.index);
return (typeof (that._lazyMap) === 'function')?that._lazyMap(result):result;
}
});
addProperties(that, common);
that.init();
return (typeof (fun) === 'function') ? that.map(fun) : that;
};
/* permutation */
var _permutation = function(ary) {
var that = ary.slice(),
size = factorial(that.length);
that.index = 0;
that.next = function() {
if (this.index >= size) return;
var copy = this.slice(),
digits = factoradic(this.index, this.length),
result = [],
i = this.length - 1;
for (; i >= 0; --i) result.push(copy.splice(digits[i], 1)[0]);
this.index++;
return (typeof (that._lazyMap) === 'function')?that._lazyMap(result):result;
};
return that;
};
// which is really a permutation of combination
var permutation = function(ary, nelem, fun) {
if (!nelem) nelem = ary.length;
if (nelem < 1) throw new RangeError;
if (nelem > ary.length) throw new RangeError;
var size = P(ary.length, nelem),
sizeOf = function() {
return size;
},
that = Object.create(ary.slice(), {
length: {
get: sizeOf
}
});
hideProperty(that, 'cmb');
hideProperty(that, 'per');
addProperties(that, {
valueOf: function() {
return size;
},
init: function() {
this.cmb = combination(ary, nelem);
this.per = _permutation(this.cmb.next());
},
next: function() {
var result = this.per.next();
if (!result) {
var cmb = this.cmb.next();
if (!cmb) return;
this.per = _permutation(cmb);
return this.next();
}
return (typeof (that._lazyMap) === 'function')?that._lazyMap(result):result;
}
});
addProperties(that, common);
that.init();
return (typeof (fun) === 'function') ? that.map(fun) : that;
};
/* export */
var Combinatorics = Object.create(null);
addProperties(Combinatorics, {
C: C,
P: P,
factorial: factorial,
factoradic: factoradic,
permutation: permutation,
});
return Combinatorics;
})();
function permute_Technicalbloke(inputArray) {
if (inputArray.length === 1) return inputArray;
return inputArray.reduce( function(accumulator,_,index){
permute_Technicalbloke([...inputArray.slice(0,index),...inputArray.slice(index+1)])
.map(value=>accumulator.push([inputArray[index],value]));
return accumulator;
},[]);
}
var suite = new Benchmark.Suite;
var input = [0, 1, 2, 3, 4];
suite.add('permute_SiGanteng', function() {
permute_SiGanteng(input);
})
.add('permute_delimited', function() {
permute_delimited(input);
})
.add('permute_monkey', function() {
permute_monkey(input);
})
.add('permute_Oriol', function() {
permute_Oriol(input);
})
.add('permute_MarkusT', function() {
permute_MarkusT(input);
})
.add('permute_le_m', function() {
permute_le_m(input);
})
.add('permute_Urielzen', function() {
permute_Urielzen(input);
})
.add('permute_Taylor_Hakes', function() {
permute_Taylor_Hakes(input);
})
.add('permute_Combinatorics', function() {
Combinatorics.permutation(input).toArray();
})
.add('permute_Technicalbloke', function() {
permute_Technicalbloke(input);
})
.on('cycle', function(event) {
console.log(String(event.target));
})
.on('complete', function() {
console.log('Fastest is ' + this.filter('fastest').map('name'));
})
.run({async: true});
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/platform/1.3.4/platform.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/benchmark/2.1.4/benchmark.min.js"></script>
Run-time results for Chrome 48:
I have improved SiGanteng's answer.
Now it is possible to call permute
more than once, because permArr
and usedChars
are cleared each time.
function permute(input) {
var permArr = [],
usedChars = [];
return (function main() {
for (var i = 0; i < input.length; i++) {
var ch = input.splice(i, 1)[0];
usedChars.push(ch);
if (input.length == 0) {
permArr.push(usedChars.slice());
}
main();
input.splice(i, 0, ch);
usedChars.pop();
}
return permArr;
})();
}
function permute(input) {
var permArr = [],
usedChars = [];
return (function main() {
for (var i = 0; i < input.length; i++) {
var ch = input.splice(i, 1)[0];
usedChars.push(ch);
if (input.length == 0) {
permArr.push(usedChars.slice());
}
main();
input.splice(i, 0, ch);
usedChars.pop();
}
return permArr;
})();
}
document.write(JSON.stringify(permute([5, 3, 7, 1])));
Answer without the need for a exterior array or additional function
function permutator (arr) {
var permutations = [];
if (arr.length === 1) {
return [ arr ];
}
for (var i = 0; i < arr.length; i++) {
var subPerms = permutator(arr.slice(0, i).concat(arr.slice(i + 1)));
for (var j = 0; j < subPerms.length; j++) {
subPerms[j].unshift(arr[i]);
permutations.push(subPerms[j]);
}
}
return permutations;
}
"use strict";
function getPermutations(arrP) {
var results = [];
var arr = arrP;
arr.unshift(null);
var length = arr.length;
while (arr[0] === null) {
results.push(arr.slice(1).join(''));
let less = null;
let lessIndex = null;
for (let i = length - 1; i > 0; i--) {
if(arr[i - 1] < arr[i]){
less = arr[i - 1];
lessIndex = i - 1;
break;
}
}
for (let i = length - 1; i > lessIndex; i--) {
if(arr[i] > less){
arr[lessIndex] = arr[i];
arr[i] = less;
break;
}
}
for(let i = lessIndex + 1; i<length; i++){
for(let j = i + 1; j < length; j++){
if(arr[i] > arr[j] ){
arr[i] = arr[i] + arr[j];
arr[j] = arr[i] - arr[j];
arr[i] = arr[i] - arr[j];
}
}
}
}
return results;
}
var res = getPermutations([1,2,3,4,5]);
var out = document.getElementById('myTxtArr');
res.forEach(function(i){ out.value+=i+', '});
textarea{
height:500px;
width:500px;
}
<textarea id='myTxtArr'></textarea>
Outputs lexicographically ordered permutations. Works only with numbers. In other case, you have to change the swap method on line 34.
Here is a minimal ES6 version. The flatten and without functions can be pulled from Lodash.
const flatten = xs =>
xs.reduce((cum, next) => [...cum, ...next], []);
const without = (xs, x) =>
xs.filter(y => y !== x);
const permutations = xs =>
flatten(xs.map(x =>
xs.length < 2
? [xs]
: permutations(without(xs, x)).map(perm => [x, ...perm])
));
Result:
permutations([1,2,3])
// [[1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1]]
I wrote a post to demonstrate how to permute an array in JavaScript. Here is the code which does this.
var count=0;
function permute(pre,cur){
var len=cur.length;
for(var i=0;i<len;i++){
var p=clone(pre);
var c=clone(cur);
p.push(cur[i]);
remove(c,cur[i]);
if(len>1){
permute(p,c);
}else{
print(p);
count++;
}
}
}
function print(arr){
var len=arr.length;
for(var i=0;i<len;i++){
document.write(arr[i]+" ");
}
document.write("<br />");
}
function remove(arr,item){
if(contains(arr,item)){
var len=arr.length;
for(var i = len-1; i >= 0; i--){ // STEP 1
if(arr[i] == item){ // STEP 2
arr.splice(i,1); // STEP 3
}
}
}
}
function contains(arr,value){
for(var i=0;i<arr.length;i++){
if(arr[i]==value){
return true;
}
}
return false;
}
function clone(arr){
var a=new Array();
var len=arr.length;
for(var i=0;i<len;i++){
a.push(arr[i]);
}
return a;
}
Just call
permute([], [1,2,3,4])
will work. For details on how this works, please refer to the explanation in that post.