How to use hex() without 0x in Python?

Question

The hex() function in python, puts the leading characters 0x in front of the number. Is there anyway to tell it NOT to put them? So 0xfa230

Answer 1

Old style string formatting:

In [3]: "%02x" % 127
Out[3]: '7f'

New style

In [7]: '{:x}'.format(127)
Out[7]: '7f'

Using capital letters as format characters yields uppercase hexadecimal

In [8]: '{:X}'.format(127)
Out[8]: '7F'

Docs are here.

Answer 2

Use this code:

'{:x}'.format(int(line))

it allows you to specify a number of digits too:

'{:06x}'.format(123)
# '00007b'

For Python 2.6 use

'{0:x}'.format(int(line))

or

'{0:06x}'.format(int(line))

Answer 3

You can simply write

hex(x)[2:]

to get the first two characters removed.

Answer 4

Python 3.6+:

>>> i = 240
>>> f'{i:02x}'
'f0'

Answer 5

>>> format(3735928559, 'x')
'deadbeef'