Rendering Partial Views using ajax

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不知归路
不知归路 2020-11-28 04:10

I\'ve checked this question and it solved my initial problems. But I don\'t want the partial view to be rendered only when the user clicks a link, I want to render partial v

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  • 2020-11-28 04:24

    You can render it in the initial page by writing @Html.Partial(...).

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  • 2020-11-28 04:26

    Controller

    public ActionResult GetModule(string partialName){
        return PartialView("~/Views/Shared/"+partialName);
    }
    

    on the Default Page (using jquery ajax operation)

    <div id='mod1'>Loading...</div>
    <script type="text/javascript">
                $("#mod1").load("/ControllerName/GetModule?partialName=test1");         
    </script>
    
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  • 2020-11-28 04:35

    If you want to load the page and then load the partial view via ajax you could create an ActionMethod that does something like:

    public ActionResult Create()
    {
         var model = new MyModel();
    
         if (Request.IsAjaxRequest())
         {
              return PartialView( "_Partial", model.PartialModel );
         }
         else
         {
              return View( model );
         } 
    }
    

    and then in your page do something like:

    $(function(){
    
        $(document).ajaxStart(function () {
            //show a progress modal of your choosing
            showProgressModal('loading');
        });
        $(document).ajaxStop(function () {
            //hide it
            hideProgressModal();
        });
    
        $.ajax({
              url: '/controller/create',
              dataType: 'html',
              success: function(data) {
                 $('#myPartialContainer').html(data);
              }
        });
    });
    
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